The answer is Option A.
Scale Factors
If the Scale Factor IS 1, the polygon stays the SAME.
(If an equilateral triangle has a side length of 8 and the scale factor is 1, the sides will stay at 8)
If the Scale Factor is MORE THAN 1, the polygon's sides INCREASE depending on what the scale factor is.
(If a square has a side length of 3 and the scale factor is 4, the sides will increase to 12)
If the Scale Factor is LESS THAN 1, the polygon's sides DECREASE depending on what the scale factor is.
(If a square has a side length of 5 and the scale factor is 1/2, the side lengths will decrease down to 0.5)
Therefore each side length of the new triangle is 4 times shorter than the original (Option A)
Answer:
Option D
Step-by-step explanation:
The complete question is attached herewith.
Also the options for the same are as follows -
What is the meaning of the slope of the trend line shown on the scatterplot?
A A plant grows about 3 inches for every 2 hours of sunlight it receives.
B A plant grows about 2 inches for every 3 hours of sunlight it receives.
C A plant grows about 3 inches for every 1 hour of sunlight it receives.
D A plant grows about 1 inch for every 3 hours of sunlight it receives.
Solution
If we look at the graph, we can see that in 6 hours the tomato plant grew by 2 inches.
At the X axis, when x = 6 hours, the y co-ordinate at X = 6 hours is 2 inches.
Hence, It can be interpreted that 1 inch of the tomato plant grows in 3 hours.
Hence, option D is correct
Step-by-step explanation:
i don't know sister/ boy
Answer:
Step-by-step explanation:
<h3>What are the definitions?</h3>
- Obtuse triangle - the triangle with angle greater than 90°;
- Acute triangle - the triangle with all interior angles under 90°;
- Isosceles triangle - the triangle with a pair of equal sides;
- Scalene triangle - the triangle with all three sides (or angles) of different measure.
<h3>What we have?</h3>
- All sides are different and all angles are under 90°.
<h3>Which option is correct?</h3>
Answer :
no. of days used to repair 1250m of road = 5
no. of days used to repair 1m of road = 5/1250
no. of days used to repair 8000m of road (8*1000m ) = 5/1250*8000= 32 days
