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3 years ago

What is the solution of 6(7-2x)+7=49

Mathematics

1 answer:

Oliga [24]3 years ago

8 0

Step-by-step explanation:

I think the answer is -x=7

and I cant be bothered to write the full thing out so your gonna have to wait for someone else

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Find x.______________a0

velikii [3]

Answer:

$x=4$

Step-by-step explanation:

Before we find x, we need to set up this triangle a little more. We need to find the triangle's altitude before we can solve for x. We will use the heartbeat method to find the altitude.

Let altitude = y; solve for y:

$\frac{2}{y}=\frac{y}{6}$

$y^2=12$

$y=\sqrt{12}$

$y=2\sqrt{3}$

Now that we know the altitude, we can use the Pythagorean Theorem to find the hypotenuse (x).

$a^2+b^2=c^2$

$2^2+(2\sqrt{3})^2=c^2$

$4+12=c^2$

$c^2=16$

$c=4$

Since c and x are the same; c is just the hypotenuse in the Pythagorean Theorem.

$x=4$

4 0

3 years ago

Regina rolls a fair, six-sided die every week, and her allowance for that week is twice the number she rolls on the die. Write a

Scilla [17]

Allowance =2n.
........

3 0

4 years ago

A sample of 81 account balances of a credit company showed an average balance of $1,200 with a standard deviation of $126.

TEA [102]

Answer:

(a) Null Hypothesis, $H_0$ : $\mu$ = $1,150

Alternate Hypothesis, $H_A$ : $\mu$ $\neq$ $1,150

(b) The test statistic is 3.571.

(c) We conclude that the mean of all account balances is significantly different from $1,150.

Step-by-step explanation:

We are given that a sample of 81 account balances of a credit company showed an average balance of $1,200 with a standard deviation of $126.

We have test the hypothesis to determine whether the mean of all account balances is significantly different from $1,150.

Let $\mu$ = mean of all account balances

(a)So, Null Hypothesis, $H_0$ : $\mu$ = $1,150 {means that the mean of all account balances is equal to $1,150}

Alternate Hypothesis, $H_A$ : $\mu$ $\neq$ $1,150 {means that the mean of all account balances is significantly different from $1,150}

The test statistics that will be used here is One-sample t test statistics as we don't know about population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample average balance = $1,200

s = sample standard deviation = $126

n = sample of account balances = 81

(b) So, test statistics = $\frac{1,200-1,150}{\frac{126}{\sqrt{81} } }$ ~ $t_8_0$

= 3.571

The value of the sample test statistics is 3.571.

(c) Now, P-value of the test statistics is given by the following formula;

P-value = P( $t_8_0$ > 3.571) = Less than 0.05%

Because in the t table the highest critical value for t at 80 degree of freedom is given between 3.460 and 3.373 at 0.05% level.

Now, since P-value is less than the level of significance as 5% > 0.05%, so we sufficient evidence to reject our null hypothesis.

Therefore, we conclude that the mean of all account balances is significantly different from $1,150.

8 0

4 years ago

Which of the following function is graphed?

Thepotemich [5.8K]

Answer:

Step-by-step explanation:

Try to remember this formula.

$y=a|b(x-c)|+d$

Where a is the vertical multiplier, b is the horizontal multiplier, c is the x coordinate of the vertex, and d is the y coordinate of the vertex.

Since the vertex on the graph is (2,3), c and d have to be 2 and 3.

Also, there are no vertical/horizontal stretches so the a and b values stay at 1.

The final equation would come out to $y=|x-2|+3$

4 0

3 years ago

CAN SOMEONE PLEASE ANSWER THIS QUICK.

Svetach [21]

3 12111/20000

9 38083/100000

10 1247/25000

4 0

4 years ago