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3 years ago

denise constructs a triangle with angles measuring 64o and 32o. what would the third angle measurement be

Mathematics

2 answers:

Aliun [14]3 years ago

6 0

Answer:

Step-by-step explanation:

Let the third angle be x

Sum of all angles of an triangle = 180

64+32+x=180

96+x=180

X=180-96

X=84

kherson [118]3 years ago

4 0

Answer:

The third angle measurement would be 84 degrees.

Step-by-step explanation:

When you add together all the inner angles of the triangle, they should equal 180 degrees. 32 and 64 make 96. To reach 180, you have to add 84.

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93 is decreased to 90

lapo4ka [179]

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5 0

4 years ago

FIND THE AREA AND PERIMETER PLEASE

baherus [9]

Answer:

Area = 70 Perimeter = 50

Step-by-step explanation:

I will begin with area. I can find the area of each figure, then add the areas.

3 • 18 = 54

4 • 4 = 16

Area = 70

For perimeter, I will add the given lengths.

3 + 18 + 7 + 4 + 4 + 14

Perimeter = 50

8 0

3 years ago

Read 2 more answers

The triangles below are similar. Triangle A B C. Side A C is 10 and side A B is 5. Angle C is 30 degrees. Triangle D E F. Side E

Gnoma [55]

Answer:

$\triangle ABC {\displaystyle \sim } \triangle DE\ F$

$\triangle CBA {\displaystyle \sim } \triangle FED$

$\triangle BAC {\displaystyle \sim } \triangle EDF$

Step-by-step explanation:

Given

$\triangle ABC {\displaystyle \sim } \triangle DE\ F$

$AC = 10$

$AB = 5$

$\angle C = 30^\circ$

$ED = 7.5$

$DF = 25$

$\angle F =30$

$\angle E =90$

Required

Which of the options is/are true:

$\triangle CBA {\displaystyle \sim } \triangle FED$ $\triangle CBA {\displaystyle \sim } \triangle FDE$ $\triangle BAC {\displaystyle \sim } \triangle EFD$

$\triangle BAC {\displaystyle \sim } \triangle EDF$ $\triangle ABC {\displaystyle \sim } \triangle DE\ F$ $\triangle ABC {\displaystyle \sim } \triangle DFE$