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Arisa [49]
2 years ago
14

Which of the following ratios is equal to 14 : 21? (2 : 3) (1 : 3) (2 : 5) (1 : 2)​

Mathematics
2 answers:
anzhelika [568]2 years ago
4 0

Answer:

(2:3)

Step-by-step explanation:

pashok25 [27]2 years ago
3 0
It’s 2/3 ,because 14/21 in simplest form is 2/3 .
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What are the domain and range of each relation? Drag the answer into the box to match each relation. A mapping diagram. Element
ra1l [238]

Answer:

Domain: {−2, −1, 0, 2} Range: {−4, −2, 2}

Step-by-step explanation:

We have been given a mapping diagram as shown below:

X Y

-2 -4

-1 -2

0 2

2


For better view, you can check the attached mapping diagram.

From that diagram we have to find domain and range.

Domain contains only x values so domain will be:

Domain: {-2,-1,0,2}

Range contains only y values so range will be:

Range: {-4,-2,2}

We see that only third choice matches obtained values of domain and range.

Hence final answer is  Domain: {−2, −1, 0, 2} Range: {−4, −2, 2}

7 0
2 years ago
WILL GIVE BRAINLYIST
marysya [2.9K]

Answer:

64 degrees

Step-by-step explanation:

Since the triangles are similar they have the same angle measures

\frac{PR}{PQ} =\frac{SU}{ST}          \frac{21}{14}= \frac{6}{4}

∠P = ∠S ∠R =∠U ∠Q=∠T

We know 2 of the angle measures: ∠S and ∠R, and since they are similar we know ∠P and ∠U

In triangles the sum of all angle measures is always 180 degrees, so we can solve for ∠Q with this formula

A+B+C=180

46+70+C+180

116+C=180

subtract 116 from both sides

C=64

Therefore ∠Q is equal to 64 degrees

3 0
3 years ago
Solve for x. The triangles in each pair are similar
liubo4ka [24]
9x +1= 0
9x/9 +1-1=0
X= 9-1
X= 8
3 0
2 years ago
If a spring is oscillating (moving) according to the velocity equation v(t) = 2sin(t) (in ft/s), then what is its displacement o
Feliz [49]

ANSWER

4 ft

EXPLANATION

The velocity equation of the oscillating spring is given by the function.

v(t)=2  \sin(t)   \:  \:  {ms}^{ - 1}

To find the displacement function, we need to to Integrate the velocity function.

s(t) = \int \: 2 \sin(t) dt

s(t) =  -  2 \cos(t)  + k

At time t=0, there was no displacement.

This implies that,

s(0) = 0

0=  -  2 \cos(0)  + k

0=  -  2 + k

k = 2

The displacement function then becomes,

s(t) =  -  2 \cos(t)  + 2

To find the displacement over the first π seconds, we put

t = \pi

into the equation for the displacement to get,

s(\pi) =  -  2 \cos(\pi)  + 2

s(\pi) =  -  2 ( - 1)  + 2

s(\pi) =  2  + 2 =4 ft

7 0
3 years ago
WHOEVER SOLVES IS A GENIUS!
Julli [10]
I HAVE NO IDEA WHAT THE ANSWER IS!!! CAN YOU TELL ME???
7 0
3 years ago
Read 2 more answers
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