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SpyIntel [72]
3 years ago
6

Can u give an explanation for the answer

Mathematics
1 answer:
Ber [7]3 years ago
5 0

Answer:

There are 8 quarters in the jar.

Step-by-step explanation:

There are 20 coins in a jar.

Each coin is either a nickel or a quarter.

The probability of selecting a nickel is 0.6

Let's assume there are x number of nickels

The probability of selecting a nickel coin is \frac{x}{20} = 0.6

So x = 0.6 × 20 = 12

Hence there are are 12 nickel coins and 20 - 12 = 8 quarter coins.

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Suppose you do a favor for 3 people then you ask each of them to do a favor for 3 more people
Ilya [14]
Well Wouldn’t that be 6? Because you asked 3 people to do a favor then you,ask each of them to do a favor for 3 more people easy 3+3=6.Hope this helps!
5 0
3 years ago
Read 2 more answers
If AC=3x, AB=15, and BC=2x-1, how could we solve for x? A. Set 3x=15 B. Set 3x=2x-1 C. Set 3x+15=2x-1 D. Set 3x=15+ (2x-1) E. No
k0ka [10]
Hmm this is a very challenging question good luck finding someone who can answer it lol
5 0
3 years ago
Find the nth term of 8, 2, -4, -10,... then find A50
kumpel [21]

Answer:

An=8+(n-1)(-6)

=8-6n+6

=14-6n

A50=14-6(50)

= -286

7 0
3 years ago
Part A is asking how long the bridge is and Part B is asking how expensive it would be if each foot it 1500
katrin [286]

Answer:

(a)80 feet

(b)$120,000

Step-by-step explanation:

<u>Part A</u>

<u>Intersecting Secant-Tangent Theorem</u>

If a tangent segment and a secant segment are drawn to a circle from an exterior point, then the square of the measure of the tangent segment is equal to the product of the measures of the secant segment and its external secant segment.

In the attached diagram, the theorem applied is:

|AX|^2=|UX|*|TX|

Comparing with our diagram:

|AX|=30 feet

|UX|=10 feet

Length of the Bridge,L

Therefore:

30^2=10 X ($Length of the Bridge+10)

900=10(L+10)

L+10=900/10

L+10=90

L=90-10=80 feet

Length of the Bridge=80 feet

<u>Part B</u>

If each foot costs $1500

Cost of the bridge=$1500*80=$120,000

4 0
3 years ago
Suppose that the sitting​ back-to-knee length for a group of adults has a normal distribution with a mean of mu equals 24.4 in.
solong [7]

Answer:

P(X \geq 26.6) = 0.0336, which is greater than 0.01. So a back-to-knee length of 26.6 in. is not significantly high.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 24.4, \sigma = 1.2

In this problem, a value x is significantly high if:

P(X \geq x) = 0.01

Using these​ criteria, is a​ back-to-knee length of 26.6 in. significantly​ high?

We have to find the probability of the length being 26.6 in or more, which is 1 subtracted by the pvalue of Z when X = 26.6. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{26.6 - 24.4}{1.2}

Z = 1.83

Z = 1.83 has a pvalue of 0.9664.

1 - 0.9664 = 0.0336

P(X \geq 26.6) = 0.0336, which is greater than 0.01. So a back-to-knee length of 26.6 in. is not significantly high.

6 0
3 years ago
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