2x2−5x=3
I think the first step would be to
Subtract 3 from both sides
2x2−5x−3=3−3
2x2−5x−3=0
Then
For this equation: a=2, b=-5, c=-3
2x2+−5x+−3=0
Lastly you would
Use quadratic formula with a=2, b=-5, c=-3
I think your answer would then have to be...
x = 3 or x = −1
/2
I found width=13.72 ft and length=43.72 ft.
Call one dimension of the rectangle x, the other will be x+30
You want an area A=600 ft^2 but A=length x width=x*(x+30)=600
Rearranging you get:

solving this quadratic equation you get a negative solution and a positive one that gives your result.
Using the product rule, we have

so that

The equation of the tangent line to <em>W(x)</em> at <em>x</em> = 7 has all the information we need to determine <em>m'</em> (7).
When <em>x</em> = 7, the tangent line intersects with the graph of <em>W(x)</em>, and
<em>y</em> = 4.5 + 2 (7 - 7) ==> <em>y</em> = 4.5
means that this intersection occurs at the point (7, 4.5), and this in turn means <em>W</em> (7) = 4.5.
The slope of this tangent line is 2, so <em>W'</em> (7) = 2.
Then

Sorry I can’t see the pic