A student examines a sample of pond water under a microscope and observes a single-celled heterotrophic eukaryote swimming throu
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Answer:
.45 from mom, .05 from dad
Explanation:
Given that:
the mother's genotype is AZ/az
i.e AZ = 50%
az = 50% (parental)
But we were also told that the recombination rate is 10% which will like wise affect the mother's genotype
So 100% -10% = 90 % of the mother's genotype
We have a new genotype
AZ = 45%
az = 45% (parental)
Therefore the probability of az gamete from the mother =
= 0.45
Similarly; the genotype of the father is: Az/aZ
This is an heterozygous father who is diploid hence, there is a remarkable presence of two copies of each autosomal chromosome.
Az is the allele of the genes in one chromosomes and aZ is the allele of the genes in the other.
The gametes of this self cross are: Aa, AZ, az, zZ
Therefore; the recombinants are:
AZ
az
Since there are 10% recombinant; then
AZ = 5%
az = 5%
Therefore the probability of az gamete from the father =
= .05