Answer:
A^2 + B^2 = C^2
Step-by-step explanation:
The applies for right triangle where C is the hypotenuse.
b = base length (of triangle)
h = height of triangle
s = side length of triangle
l = length of rectangle
Answer:
0.0143 in decimal form
Step-by-step explanation:
Here we have a problem of probability, we will find that the probability of landing in heads is M/N = 1/3, then we have:
M + N = 1 + 3 = 4.
Let's see how we got that:
Let's define:
p = probability of landing on tails
q = probability of landing on heads.
The probability of getting at least one tails in 3 tosses is 26/27
This means that the probability of not getting tails in the 3 tosses is:
P = 1 - 26/27 = 1/27
And the case where you do not get any tails in the 3 tosses, means that in all the 3 tosses you got heads.
The probability of getting 3 heads in a row is:
P = q^3 = 1/27
Solving for q, we get:
q = ∛(1/27) = 1/3
Now we want to express q = M/N = 1/3
then we have:
M = 1
N = 3
Now we want to compute M + N = 1 + 3 = 4
If you want to learn more about probability, you can read:
brainly.com/question/24369877
<span>The median would be preferred over the mean in such scenarios because the median will lessen the impact of the outliers that fall within the "tail" of the skew. Therefore, if a curve is normally distributed, that is to say that data is normally distributed, there will be two tails, each with approximately equal proportions of outliers. Outliers in this case being more extreme numbers, and are based on your determination depending on how you are using the data. If data is skewed there is one tail, and therefore it may be an inaccurate measure of central tendency if you use the mean of the numbers. Thinking of this visually. In positively skewed data where there is a "tail" towards the right and a "peak" towards the left, the median will be placed more in the "peak", whereas the mean will be placed more towards the "tail", making it a poorer measure of central tendency, or the center of the data.</span>
