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BartSMP [9]
3 years ago
10

Solve the system of equations -5y-10x=45. -3y+10x=-5 x= y=

Mathematics
1 answer:
yKpoI14uk [10]3 years ago
8 0

Answer:

x  = -2

y = - 5

Step-by-step explanation:

-5y - 10x = 45

-3y + 10x = -5

------------------------Add

-8y = 40

  y = -5

-3(-5) + 10x = -5

15 + 10x = -5

10x = -20

  x = -2

Answer

x  = -2 and y = - 5

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A pair of shoes is currently priced at $55.00. If the store manager marks it down to $22.00, by what percent did he mark down th
telo118 [61]

Answer:

60%

Step-by-step explanation:

55 - 22 = 33

33/55 = 0.6

0.6*100 = 60%

6 0
3 years ago
What is the value of x?
liq [111]
An exterior angle is equal to the sum of the 2 non adjacent angles. In this case

100 = x + 70 Subtract 70
x = 100 - 70
x = 30
6 0
3 years ago
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In a certain community, 30% of the families own a dog, and 20% of the families that own a dog also own a cat. It is also known t
Komok [63]

Answer:

What is the probability that a randomly selected family owns a cat? 34%

What is the conditional probability that a randomly selected family doesn't own a dog given that it owns a cat? 82.4%

Step-by-step explanation: We can use a Venn (attached) diagram to describe this situation:

Imagine a community of 100 families (we can assum a number, because in the end, it does not matter)

So, 30% of the families own a dog = .30*100 = 30

20% of the families that own a dog also own a cat = 0.2*30 = 6

34% of all the families own a cat = 0.34*100 = 34

Dogs and cats: 6

Only dogs: 30 - 6 = 24

Only cats: 34 - 6 = 28

Not cat and dogs: 24+6+28 = 58; 100 - 58 = 42

What is the probability that a randomly selected family owns a cat?

34/100 = 34%

What is the conditional probability that a randomly selected family doesn't own a dog given that it owns a cat?

A = doesn't own a dog

B = owns a cat

P(A|B) = P(A∩B)/P(B) = 28/34 = 82.4%

5 0
2 years ago
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What is the inverse of the function​
sleet_krkn [62]

Answer:

x^2-10x+31

Step-by-step explanation:

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x=\sqrt{y-6}+5

\sqrt{y-6}+5=x

\sqrt{y-6}+5-5=x-5

\sqrt{y-6}=x-5

\left(\sqrt{y-6}\right)^2=\left(x-5\right)^2

\left(\sqrt{y-6}\right)^2

=\left(\left(y-6\right)^{\frac{1}{2}}\right)^2

=y-6

\left(x-5\right)^2

=x^2-10x+25

y-6=x^2-10x+25

y-6+6=x^2-10x+25+6

y=x^2-10x+31

6 0
2 years ago
PLEASE HELP ME THIS IS DUE IN TWO HOURS! :(
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Answer:224 squared

Step-by-step explanation:

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