- Given, x > 0, y > 0.
- So, the values of x and y are less than 0, that means, they are negative integers.
- If we divide a Cartesian plane with the x-axis and y-axis, we get four quadrants.
- 1st Quadrant : (+,+)
- 2nd Quadrant : (-,+)
- 3rd Quadrant : (-,-)
- 4th Quadrant : (+,-)
- Since the values of x and y are both negative, so (x, y) is located in the <em><u>3rd Quadrant</u></em>.
Hope you could get an idea from here.
Doubt clarification - use comment section
Answer: Dimensions of A are of length [L]
Dimensions of B are of 
Dimensions of C are of 
Step-by-step explanation:
The given equation is

Since the dimension on the L.H.S of the equation is [L] , each of the terms on the right hand side should also have dimension of length[L] to be dimensionally valid
Thus
Dimensions of A = [L]
Dimensions of Bt = [L]
![Bt=[L]\\\\](https://tex.z-dn.net/?f=Bt%3D%5BL%5D%5C%5C%5C%5C)
![[B][T]=[L]](https://tex.z-dn.net/?f=%5BB%5D%5BT%5D%3D%5BL%5D)
![\\\\\therefore [B]=LT^{-1}](https://tex.z-dn.net/?f=%5C%5C%5C%5C%5Ctherefore%20%5BB%5D%3DLT%5E%7B-1%7D)
Similarly
Dimensions of ![Ct^{}2 = [L]](https://tex.z-dn.net/?f=Ct%5E%7B%7D2%20%3D%20%5BL%5D)
![Ct^{2}=[L]\\\\[C][T]^{2}=[L]\\\\\therefore [C]=LT^{-2}](https://tex.z-dn.net/?f=Ct%5E%7B2%7D%3D%5BL%5D%5C%5C%5C%5C%5BC%5D%5BT%5D%5E%7B2%7D%3D%5BL%5D%5C%5C%5C%5C%5Ctherefore%20%5BC%5D%3DLT%5E%7B-2%7D)
Answer:
1/18?
Step-by-step explanation:
Answer:
ADSFGZRxjtkcyluv
Step-by-step explanation:
DAFSGZHjkh