Question

Write and implement an interactive C program to scan and process a stream of words of a plain text. Your program should start with an empty list of words. (Combinations of blanks, tabs, and newline characters to separate words.) After reading each word from the input stream, check the word for punctuation marks: if the first letter of the word is preceded or the last letter is followed by punctuation marks, delete punctuation marks from the word if a word contains punctuation marks in the middle, ignore the letters beyond these punctuation marks. For example, if the word is fish, (fish comma) then the resulting word should be fish however, if the word is fish_net then the resulting word would be fish.

Answer 1

Answer:

(c) A list of words

Explanation:First let's format the code properly

fin = open('words.txt')

for line in fin:

    word = line.strip()

    print(word)

Second, let's explain each line of the code

Line 1:

The open() function is a built-in function that takes in, as argument, the name of a file, and returns a file object that can be used to read the file.

In this case, the name of the file is words.txt. Therefore, the variable fin is a file object which contains the content of the file - words.txt

Line 2:

The for loop is used to read in each line of the content of the file object (fin).

Line 3:

Each line of the contents is stripped to remove any trailing and leading white spaces by calling on the strip() function. The result of the strip is stored in the variable word.

Line 4:

The content of word at each of the cycles of the loop is printed to the console.

Therefore,  the overall output of the program is a list of words where each word represents a line in the target file (words.txt)