Answer:
=((SUM(PUT RANGE OF MOTHLY EXPENSES HERE)*12)+SUM(PUT RANGE OF YEARLY EXPENSES HERE))/12
Explanation:
Adds all of the Monthly Expenses : SUM(PUT RANGE OF MOTHLY EXPENSES HERE)
Multiplies the result by 12: *12
Then adds all of the Yearly Expenses to the product of Steps 1 and 2 : SUM(PUT RANGE OF YEARLY EXPENSES HERE)
Divides this new sum by 12: /12
=((SUM(PUT RANGE OF MOTHLY EXPENSES HERE)*12)+SUM(PUT RANGE OF YEARLY EXPENSES HERE)/12)
Complete Question:
Recall that with the CSMA/CD protocol, the adapter waits K. 512 bit times after a collision, where K is drawn randomly. a. For first collision, if K=100, how long does the adapter wait until sensing the channel again for a 1 Mbps broadcast channel? For a 10 Mbps broadcast channel?
Answer:
a) 51.2 msec. b) 5.12 msec
Explanation:
If K=100, the time that the adapter must wait until sensing a channel after detecting a first collision, is given by the following expression:
The bit time, is just the inverse of the channel bandwidh, expressed in bits per second, so for the two instances posed by the question, we have:
a) BW = 1 Mbps = 10⁶ bps
⇒ Tw = 100*512*(1/10⁶) bps = 51.2*10⁻³ sec. = 51.2 msec
b) BW = 10 Mbps = 10⁷ bps
⇒ Tw = 100*512*(1/10⁷) bps = 5.12*10⁻³ sec. = 5.12 msec
Answer:
The Title Bar displays the name of the open file and the program.
