1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
olga_2 [115]
2 years ago
9

Ameekah is working with consecutive integers

Mathematics
2 answers:
Irina-Kira [14]2 years ago
7 0

Consecutive numbers: 1, 2, 3, 4, 5.

As we can see it's the latest plus 1

So,

x, x + 1, x + 1 + 1, x + 1 + 1 + 1

x, x + 1, x + 2, x + 3 and so on

So it's x + 1.

choli [55]2 years ago
5 0

For this case we have that by definition, a consecutive number is obtained by adding a unit to the previous one.

Example:

n, n + 1, n + 2, n + 3 ...

So:

If "x" is the first number of Ameekah, its second number to form a series of consecutive integers must be:

x + 1, that is, add "1" to the previous number.

Answer:

x + 1

Option B

You might be interested in
Put the following equation in Slope-intercept form. y=mx+b is the form you are looking for.
Elenna [48]

Answer:

y= -2x+23

Step-by-step explanation:

Subtract 2x over

7 0
2 years ago
I can't figure out how to do (i + j) x (i x j)for vector calc
Vinil7 [7]

In three dimensions, the cross product of two vectors is defined as shown below

\begin{gathered} \vec{A}=a_1\hat{i}+a_2\hat{j}+a_3\hat{k} \\ \vec{B}=b_1\hat{i}+b_2\hat{j}+b_3\hat{k} \\ \Rightarrow\vec{A}\times\vec{B}=\det (\begin{bmatrix}{\hat{i}} & {\hat{j}} & {\hat{k}} \\ {a_1} & {a_2} & {a_3} \\ {b_1} & {b_2} & {b_3}\end{bmatrix}) \end{gathered}

Then, solving the determinant

\Rightarrow\vec{A}\times\vec{B}=(a_2b_3-b_2a_3)\hat{i}+(b_1a_3+a_1b_3)\hat{j}+(a_1b_2-b_1a_2)\hat{k}

In our case,

\begin{gathered} (\hat{i}+\hat{j})=1\hat{i}+1\hat{j}+0\hat{k} \\ \text{and} \\ (\hat{i}\times\hat{j})=(1,0,0)\times(0,1,0)=(0)\hat{i}+(0)\hat{j}+(1-0)\hat{k}=\hat{k} \\ \Rightarrow(\hat{i}\times\hat{j})=\hat{k} \end{gathered}

Where we used the formula for AxB to calculate ixj.

Finally,

\begin{gathered} (\hat{i}+\hat{j})\times(\hat{i}\times\hat{j})=(1,1,0)\times(0,0,1) \\ =(1\cdot1-0\cdot0)\hat{i}+(0\cdot0-1\cdot1)\hat{j}+(1\cdot0-0\cdot1)\hat{k} \\ \Rightarrow(\hat{i}+\hat{j})\times(\hat{i}\times\hat{j})=1\hat{i}-1\hat{j} \\ \Rightarrow(\hat{i}+\hat{j})\times(\hat{i}\times\hat{j})=\hat{i}-\hat{j} \end{gathered}

Thus, (i+j)x(ixj)=i-j

8 0
1 year ago
Write the word sentence as an equation. Then solve the equation. A number multiplied by 2/3 is 3/20.
vaieri [72.5K]

Answer:

Equation = X*(2/3) = 3/20

Solve for X = 0.23

Step-by-step explanation:

Let, the number be "X"

According to the question,

X*(2/3) = 3/20..........(i)

From equation (i), we can get,

X = (3/20)/(2/3)

or, X = 0.15/0.66

or, X = 0.23

Alternative way,

Let, the number be "X"

According to the question,

X*(2/3) = 3/20..........(i)

From equation (i), we can get,

X = (3/20)/(2/3)

or, X = (3/20)*(3/2)

or, X = 9/40

or, X = 0.23

7 0
3 years ago
What is the 7-intercept of 2x-4y=12
Bingel [31]

Answer:

-3

Step-by-step explanation:

2x - 4y = 12

4y = 2x - 12

y = ½x - 3

Y intercept is -3

X intercept is 6

8 0
3 years ago
Read 2 more answers
Help me please !<br> 4,5 and 6
andreev551 [17]

9514 1404 393

Answer:

  4a. ∠V≅∠Y

  4b. TU ≅ WX

  5. No; no applicable postulate

  6. see below

Step-by-step explanation:

<h3>4.</h3>

a. When you use the ASA postulate, you are claiming you have shown two angles and the side between them to be congruent. Here, you're given side TV and angle T are congruent to their counterparts, sides WY and angle W. The angle at the other end of segment TV is angle V. Its counterpart is the other end of segment WY from angle W. In order to use ASA, we must show ...

  ∠V≅∠Y

__

b. When you use the SAS postulate, you are claiming you have shown two sides and the angle between them are congruent. The angle T is between sides TV and TU. The angle congruent to that, ∠W, is between sides WY and WX. Then the missing congruence that must be shown is ...

  TU ≅ WX

__

<h3>5.</h3>

The marked congruences are for two sides and a non-included angle. There is no SSA postulate for proving congruence. (In fact, there are two different possible triangles that have the given dimensions. This can be seen in the fact that the given angle is opposite the shortest of the given sides.)

  "No, we cannot prove they are congruent because none of the five postulates or theorems can be used."

__

<h3>6.</h3>

The first statement/reason is always the list of "given" statements.

1. ∠A≅∠D, AC≅DC . . . . given

2. . . . . vertical angles are congruent

3. . . . . ASA postulate

4. . . . . CPCTC

8 0
3 years ago
Other questions:
  • The lengths in feet of three pieces of timber are 48, 72, and 40. The sawmill operator needs to cut the timber into logs of equa
    7·1 answer
  • Which expression is equivalent to 1/5(15+10x-5)
    7·1 answer
  • What is point-slope form? When can you use point-slope form? How is it useful?
    10·1 answer
  • If UT is a midsegment of QRS, find SQ<br> A. 8 <br> B. 10 <br> C. 16 <br> D. 20
    5·1 answer
  • Plz help me show work four points correctly evaluate the function for the given value showing all work HELP PLZ
    9·1 answer
  • Simplify the following expression. 3x(4x − 3) A. 12x2 + 13x B. 12x2 + 5x C. 12x2 − 5x D. 12x2 − 9x
    11·2 answers
  • A farmer harvested 35 acres of corn and 20 acres of beans. Animals ate 18
    13·1 answer
  • Shiva read 1/2 of a book in the morning, and she read some more at night. By the end of the day, she still had 1/3 of the book l
    14·2 answers
  • PLZ HELP IT WILL HELP A LOT
    8·2 answers
  • Can you please help me with this last question? I'm stuck​
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!