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-BARSIC- [3]
3 years ago
15

Find the value of a.2004-04-01-01-00_files/i0150000.jpg

Mathematics
1 answer:
Tanzania [10]3 years ago
8 0
<span>are you familiar with the pythagorean theorem?
</span>it's the formula a^2 + b^2 = c^2 where 'a' and 'b' are the legs of a right triangle, c is the hypotenuse
so here,
<span>lets take
a = unknown, b = 18, c = 36</span><span>If we focus on triangle ABC, we see that AC is the hypotenuse If we turn our attention to triangle ADB, we'll find that AB is the hypotenuse So they are corresponding partAD is the longer leg of triangle ADB AB is the longer leg of triangle ABC so this is another pair of corresponding partswe then divide the corresponding parts of ABC over ADB (in the same order) like this AC/AB = AB/AD then plug in the info we know 36/(18*sqrt(3)) = (18*sqrt(3))/AD and then solve for ADcross multiply to get 36*AD = (18*sqrt(3))(18*sqrt(3)) 36*AD = 18*18*sqrt(3)*sqrt(3)  36*AD = 18^2*(sqrt(3))^2 36*AD = 324*3 36*AD = 972 AD = 972/36AD = 27hope u get it :)</span>
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REY [17]

Answer:  

3/4

5/8

1/2

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5 0
3 years ago
The equation a=1/2(b^1+b^2)h can be determined the area, a, of a trapezoid with height, h, and base lengths, b^1 and b^2 Which a
Evgesh-ka [11]

The complete question is as follows.

The equation a = \frac{1}{2}(b_1 + b_2 )h can be used to determine the area , <em>a</em>, of a trapezoid with height , h, and base lengths, b_1 and b_2. Which are equivalent equations?

(a) \frac{2a}{h} - b_2 = b_1

(b) \frac{a}{2h} - b_2 = b_1

(c) \frac{2a - b_2}{h} = b_1

(d) \frac{2a}{b_1 + b_2} = h

(e) \frac{a}{2(b_1 + b_2)} = h

Answer: (a) \frac{2a}{h} - b_2 = b_1; (d) \frac{2a}{b_1 + b_2} = h;

Step-by-step explanation: To determine b_1:

a = \frac{1}{2}(b_1 + b_2 )h

2a = (b_1 + b_2)h

\frac{2a}{h} = b_1 + b_2

\frac{2a}{h} - b_2 = b_1

To determine h:

a = \frac{1}{2}(b_1 + b_2 )h

2a = (b_1 + b_2)h

\frac{2a}{(b_1 + b_2)} = h

To determine b_2

a = \frac{1}{2}(b_1 + b_2 )h

2a = (b_1 + b_2)h

\frac{2a}{h} = (b_1 + b_2)

\frac{2a}{h} - b_1 = b_2

Checking the alternatives, you have that \frac{2a}{h} - b_2 = b_1 and \frac{2a}{(b_1 + b_2)} = h, so alternatives <u>A</u> and <u>D</u> are correct.

4 0
3 years ago
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trasher [3.6K]

Before we do any solving, we need to simplify both sides.

On the left, we can simplify -2x + 3x - 5 to x - 5.

On the right, we can simplify 6 - 21 to -16.

So we have x - 5 = -16.

Solving from here, we add 5 to both sides to get x = -11.

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Eduardwww [97]

Answer:

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Lunna [17]
X<-7 so the answer would be greater*




4 0
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