The cardboard sleeves reduce the heatness from the coffee cup. So then the cosumer does not get a burn.
Answer:
hope this helps
Explanation:
Carbon monoxide (CO) is an odorless, colorless gas formed by the incomplete combustion of fuels. When people are exposed to CO gas, the CO molecules will displace the oxygen in their bodies and lead to poisoning.
The letter in parentheses after a chemical formula indicates c) the physical state of the substance.
The letters can be:
→ (s) for solid.
→ (l) for liquid.
→ (g) for gazeous.
→ (aq) for an aqueous solution (like NaCl (aq) - NaCl is dissolved in water)
Answer:
w = 164.62 g
Explanation:
molarity of a solution is given as -
Molarity (M) = ( w / m ) / V ( in L)
where ,
m = molecular mass ,
w = given mass ,
V = volume of solution ,
From the question ,
M = 500 mM = 0.5 M
( since , 1 mM = 1 / 100 M)
As we know , the molecular mass of potassium ferricyanide = 329.24 g/ mol
V = vol.of solution = 1 L
w = ?
<u>To find the value of w , using the above formula , and putting the respected values , </u>
Molarity (M) = ( w / m ) / V ( in L)
0.5 = ( w / 329.24 ) / 1 L
w = 164.62 g
Answer:
124.56 moles of Hydrogen atoms.
Explanation:
We'll begin by calculating the number of moles of ethane that contains 1.25×10²⁵ molecules. This can be obtained as follow:
From Avogadro's hypothesis, 1 mole of any substance contains 6.02x10²³ molecules. This implies that 1 mole of ethane also contains 6.02x10²³ molecules.
Thus, 6.02x10²³ molecules are present in 1 mole of ethane.
Therefore, 1.25×10²⁵ molecules are present in = 1.25×10²⁵/6.02x10²³ = 20.76
Therefore, 20.76 moles of ethane contains 1.25×10²⁵ molecules.
Finally, we shall determine the number of mole of Hydrogen in 20.76 moles of ethane. This can be obtained as follow:
Ethane has formula as C2H6.
From the formula, 1 mole of ethane, C2H6 contains 6 moles of Hydrogen atoms.
Therefore, 20.76 moles of ethane will contain = 20.76 × 6 = 124.56 moles of Hydrogen atoms.
Therefore, 1.25×10²⁵ molecules of ethane contains 124.56 moles of Hydrogen atoms.
