In right ∆ABC, m B = 90°, m C = 40°, and BC = 10. What are the other two side lengths of the triangle?

How t o solve negative square root of 169 <img src="https://tex.z-dn.net/?f=%20%5Csqrt%5B%20-%20%5D%7B169%7D%20" id="TexFormu

oee [108]

The answer to the question is -13

4 0

3 years ago

Giải phương trình vi phân a. dy/dx b. y' + 2xy = 4x

WITCHER [35]

Your first differential equation is incomplete, so I'll just look at the second one.

y' + 2xy = 4x

Multiply both sides by exp(x ²):

exp(x ²) y' + 2x exp(x ²) y = 4x exp(x ²)

The left side is the derivative of a product:

(exp(x ²) y )' = 4x exp(x ²)

Integrate both sides:

exp(x ²) y = ∫ 4x exp(x ²) dx

For the integral, substitute u = x ² and du = 2x dx :

exp(x ²) y = 2 ∫ exp(u) du

Solve for y :

exp(x ²) y = 2 exp(u) + C

exp(x ²) y = 2 exp(x ²) + C

y = 2 + C exp(-x ²)

8 0

3 years ago

4(2+-3)2? I will give 10 points!

lilavasa [31]

Answer:

-8

Step-by-step explanation:

Use PEMDAS (solve for parenthesis first):

4(2 + -3)2

4(2 - 3)2

4(-1)2

(-4)2

-8

5 0

3 years ago

Read 2 more answers

As part of a study on pulse rates, a random sample of 10 study participants had their pulse rate taken and asked to sit quietly

Ivahew [28]

Answer:

$t = \frac{-1.2-0}{\frac{2.97}{\sqrt{10}}}= -1.278$

The degrees of freedom are :

$df=n-1=10-1=9$

$p_v =2*P(t_{9}$

Since the p value is a very high value is higher than the typical values for the significance level (0.05,0.1) so then we have enough evidence to FAIL to reject the null hypothesis and there is no enough evidence to conclude that the true difference in the means is different from 0. And the best conclusion would be:

d. There is not enough evidence to conclude the mean difference in pulse rates before and after the 5 minute waiting period is different from 0.

Step-by-step explanation:

We are interested to check if the true difference in pulse rates before and after after 5 minute waiting period is 0 or no so then the system of hypothesis are:

Null hypothesis: $\mu_d =0$

Alternative hypothesis: $\mu_d \neq 0$

We have the following data given:

$\bar X_d = -1.2$ sample mean for the difference

$n =10$ the sample size

$s_d = 2.97$ sample standard deviation

The statistic is given by:

$t= \frac{\bar X -\mu}{\frac{s}{\sqrt{n}}}$

And replacing we got:

$t = \frac{-1.2-0}{\frac{2.97}{\sqrt{10}}}= -1.278$

The degrees of freedom are :

$df=n-1=10-1=9$

Since we are conducting a bilateral test te p value would be given by:

$p_v =2*P(t_{9}$

Since the p value is a very high value is higher than the typical values for the significance level (0.05,0.1) so then we have enough evidence to FAIL to reject the null hypothesis and there is no enough evidence to conclude that the true difference in the means is different from 0. And the best conclusion would be:

d. There is not enough evidence to conclude the mean difference in pulse rates before and after the 5 minute waiting period is different from 0.

7 0

4 years ago

Add the polynomials 3p - 4q + 4r and q - 6p + r

svp [43]

Answer:

Step-by-step explanation:

$(3p-4q+4r)+(q-6p+r)\qquad\text{combine like terms}\\\\=(3p-6p)+(-4q+q)+(4r+r)\\\\=-3p-3q+5r$

5 0

3 years ago