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Flura [38]
3 years ago
13

To make the perfect orange color hector mixes 2/3 quarts of red paint with 1 4th Court of yellow paint. How much red paint is us

ed per quart of yellow paint
Mathematics
2 answers:
jonny [76]3 years ago
5 0
6/12 or the same thing but reduced 1/2

WELCOME!
Anton [14]3 years ago
5 0
Find the LCM (in this case, it's 12)
8/12 red
3/12 yellow
Make 3/12 a full quart by multiplying by 4
3/12 x 4/1 = 1
Since you multiplied 3/12 with 4, do the same with red
8/12 x 4/1
SIMPLIFY TO MAKE EASIER
8/3 x 1
You use 2 2/3 quarts of red paint for every quart of yellow paint
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Step-by-step explanation:

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3 determine the highest real root of f (x) = x3− 6x2 + 11x − 6.1: (a) graphically. (b) using the newton-raphson method (three it
Juliette [100K]

(a) See the first attachment for a graph. This graphing calculator displays roots to 3 decimal places. (The third attachment shows a different graphing calculator and 10 significant digits.)

(b) In the table of the first attachment, the column headed by g(x) gives iterations of Newton's Method. (For Newton's method, it is convenient to let the calculator's derivative function compute the derivative f'(x) of the function f(x). We have defined g(x) = x - f(x)/f'(x).) The result of the 3rd iteration is ...

... x ≈ 3.0473167

(c) The function h(x₁, x₂) computes iterations using the secant method. The results for three iterations of that method are shown below the table in the attachment. The result of the 3rd iteration is ...

... x ≈ 3.2291234

(d) The function h(x, x+0.01) computes the modified secant method as required by the problem statement. The result of the 3rd iteration is ...

... x ≈ 3.0477377

(e) Using <em>Mathematica</em>, the roots are found to be as shown in the second attachment. The highest root is about ...

... x ≈ 3.0466805180

_____

<em>Comment on these methods</em>

Newton's method can have convergence problems if the starting point is not sufficiently close to the root. A graphing calculator that gives a 3-digit approximation (or better) can help avoid this issue. For the calculator used here, the output of "g(x)" is computed even as the input is typed, so one can simply copy the function output to the input to get a 12-significant digit approximation of the root as fast as you can type it.

The "modified" secant method is a variation of the secant method that does not require two values of the function to start with. Instead, it uses a value of x that is "close" to the one given. For our purpose here, we can use the same h(x1, x2) for both methods, with a different x2 for the modified method.

We have defined h(x1, x2) = x1 - f(x1)(f(x1)-f(x2))/(x1 -x2).

6 0
2 years ago
Please help! I’ll give brainleist!
zvonat [6]
X and y are equal to 36.8
3 0
2 years ago
Read 2 more answers
Two siblings' ages have a sum of 64 years. The older sibling was born 6 years before their young sibling.
Elina [12.6K]

Hi!

So we have to make a system of equations here.

Let sibling 1 be O and sibling 2 be Y (for older and younger)

So:

O + Y = 64

O = 64 - Y

(Either one works)

The older sibling is 6 years older.

O = Y + 6

Make everything in terms of Y.

64 - Y = Y + 6

Same to both:

58 = 2y

2y = 58

Divide by 2 on both sides:

y = 29

Since the older sibling is 6 years older:

29 + 6 = 35

Y = 29

O = 35

Let me know if you have any questions.

4 0
2 years ago
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