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MArishka [77]
3 years ago
14

25 pts! If programmers cannot write an algorithm because the problem is too complex, which methodology can they use to reach an

approximate solution?
A.
flowcharts
B.
heuristics
C.
artificial intelligence
D.
machine language
E.
assembly language
Computers and Technology
1 answer:
Setler [38]3 years ago
3 0

Answer:

D, most likely thats what I was taught .

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A major retailer wants to enhance their customer experience and reduce losses
Mrac [35]

Answer:

Predict Demand

Explanation:

The type of Artificial Intelligence (Al) solution that would be suitable for solving this problem is "Predict Deman"

By predicting the demand of the potential consumer through the Artificial intelligence solution the retailer would be able to eliminate leftover out-of-stock scenarios because the adequate quantity of the products or demands will be provided thereby enhancing customers' experience arising from out-of-stock scenarios and reducing losses arising from the leftover.

5 0
3 years ago
Which two statements describe benefits of a block-based coding language
gladu [14]
Answer D and B I think
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2 years ago
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Andrew [12]

Don't click on this I am testing... I want the points so.

3 0
3 years ago
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Hello, my first time being here and I'm returning back from college and I'm now studying Java in college but I was stuck doing t
KengaRu [80]

Answer:

import java.time.LocalDate;

class TestWedding {

 public static void main(String[] args) {

   Person man1 = new Person("John", "Doe", LocalDate.parse("1990-05-23"));

   Person woman1 = new Person("Jane", "Something", LocalDate.parse("1995-07-03"));

   Person man2 = new Person("David", "Johnson", LocalDate.parse("1991-04-13"));

   Person woman2 = new Person("Sue", "Mi", LocalDate.parse("1997-12-01"));

   Couple cpl1 = new Couple(man1, woman1);

   Couple cpl2 = new Couple(man2, woman2);

   Wedding wed1 = new Wedding(cpl1, "Las Vegas", LocalDate.parse("2020-09-12"));

   Wedding wed2 = new Wedding(cpl2, "Hawaii", LocalDate.parse("2021-01-02"));  

   displayDetails(wed1, wed2);

 }

 public static void displayDetails(Wedding w1, Wedding w2) {

   System.out.println(w1.toString());

   System.out.println(w2.toString());

 }

}

---------------------------

class Couple {

 private Person person1;

 private Person person2;

 public Couple(Person p1, Person p2) {

   person1 = p1;

   person2 = p2;

 }

 public String toString() {

   return person1.toString() + " and " + person2.toString();

 }

}

----------------------------

import java.time.LocalDate;

import java.time.format.DateTimeFormatter;

class Person {

 private String firstName;

 private String lastName;

 private LocalDate birthDate;

 public Person(String first, String last, LocalDate bdate) {

   firstName = first;

   lastName = last;

   birthDate = bdate;

 }

 public String getFirstName() {

   return firstName;

 }

 public String toString() {

   DateTimeFormatter formatter = DateTimeFormatter.ofPattern("LLLL dd, yyyy");

   return String.format("%s %s born %s", this.firstName, this.lastName, birthDate.format(formatter));

 }

}

------------------------------------

import java.time.LocalDate;

import java.time.format.DateTimeFormatter;

class Wedding {

 private Couple couple;

 private String location;

 private LocalDate weddingDate;

 public Wedding(Couple c, String loc, LocalDate wDate) {

   couple = c;

   location = loc;

   weddingDate = wDate;

 }

 public String getLocation() {

       return this.location;

 }

 public String toString() {

   DateTimeFormatter formatter = DateTimeFormatter.ofPattern("LLLL dd, yyyy");

   return  

     couple.toString() +  

     " are getting married in " + location + " on "+

     weddingDate.format(formatter);

 }

}

Explanation:

I used overrides of toString to let each object print its own details. That's why this solution doesn't really require any getters. I implemented some to show how it's done, but you'll have to complete it. The solution shows how to think in an OO way; ie., let every class take care of its own stuff.

6 0
3 years ago
Given a Fully Associative cache with 4 lines using LRU replacement. The word size is one byte, there is one word per block, and
uranmaximum [27]

Answer:

3 bits

Explanation:

Capacity of main memory=16 Bytes=24

The number of address bits= 4 bits.

The size of the word= 1 Byte=20

The word bits=0.

Number of lines =4

Number of sets required=21

The sets bits is =1

The number of offset bits=20=0

Number of tag bits= total number of address bits - (word bits + offset bits + set bits)

= 4 - 0 -0- 1

= 3 bits

8 0
3 years ago
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