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konstantin123 [22]
3 years ago
11

Write a program that echos back any inputted integer greater than 1, and exits when a 0 is entered. Your program should use a co

nditional branch when deciding whether to echo back the integer or exit the program. It should use a jump when looping back up to run the input+echo again.
Computers and Technology
1 answer:
denpristay [2]3 years ago
7 0

Answer:

MIPS Code:

.data

newline: .asciiz "\n" #newline variable

.text

MAINLOOP:

li $v0, 5 #syscall to get user interger and store in $v0

syscall

add $a0, $zero, $v0 #moving the user input to $a0 from $v0

beq $a0, 0, EXIT #branching to EXIT when $a0 is 0

li $v0, 1 #syscall to print integer in $a0

syscall

li $v0, 4 #syscall to print newline

la $a0, newline

syscall

j MAINLOOP #jumping to MAINLOOP

EXIT:

Sample Output:

6

6

7

7

3

3

0

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Answer:

Input code:

car_makers = {'Honda': 'Japan', 'Fiat': 'Germany'}

#add Tesla and USA as corresponding value

car_makers['Tesla'] = 'USA'

#change Fiat entry to Italy instead of Germany

car_makers['Fiat'] = 'Italy'

print(car_makers)

print('Honda made in', car_makers['Honda'])

print('Fiat made in', car_makers['Fiat'])

print('Tesla made in', car_makers['Tesla'])

Explanation:

The first line is a define object in the python code, containing two entries of Honda and Fiat and their respective countries.

The python code adds an entry to the object "car maker" using the bracket notation, the tesla car from USA.

The country of the Fiat car is changed from Germany to Italy, using the bracket notation.

The output of the complete object and the individual cars is given.

<u>output of the python code:</u>

{'Honda': 'Japan', 'Fiat': 'Italy', 'Tesla': 'USA'}

Honda made in Japan

Fiat made in Italy

Tesla made in USA.

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