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Andrew [12]
3 years ago
13

F(x) = x − 2 and g(x) = x2 − 7x − 9. find f(g(−1)).

Mathematics
1 answer:
IceJOKER [234]3 years ago
4 0
f(x)=x-2;\ g(x)=x^2-7x-9\\\\g(-1)=(-1)^2-7\cdot(-1)-9=1+7-9=8-9=-1\\\\f(g(-1))=f(-1)=-1-2=-3
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Without his pencil or calculator, Joey knows that 2x³+3x²− 1 = 0 has at least one real solution. How does he know?
vova2212 [387]

Answer: Find the discriminant

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Step-by-step explanation:

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3 years ago
Which math expression means "the quotient of 39 and 13"?
Mkey [24]

Answer:  39.13

Step-by-step explanation:

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Will mark brainliest if you help!!!!!​
Katyanochek1 [597]

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3 0
3 years ago
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Alexxandr [17]

9514 1404 393

Answer:

  RS = √(b² +(c -a)²)

Step-by-step explanation:

Put the given point coordinates in the given formula:

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  • S = (x₂, y₂) = (b, c)

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  RS = √(b² +(c -a)²)

8 0
2 years ago
Given that the expression 2x^3 + mx^2 + nx + c leaves the same remainder when divided by x -2 or by x+1 I prove that m+n =-6
Alla [95]

Given:

The expression is:

2x^3+mx^2+nx+c

It leaves the same remainder when divided by x -2 or by x+1.

To prove:

m+n=-6

Solution:

Remainder theorem: If a polynomial P(x) is divided by (x-c), thent he remainder is P(c).

Let the given polynomial is:

P(x)=2x^3+mx^2+nx+c

It leaves the same remainder when divided by x -2 or by x+1. By using remainder theorem, we can say that

P(2)=P(-1)              ...(i)

Substituting x=-1 in the given polynomial.

P(-1)=2(-1)^3+m(-1)^2+n(-1)+c

P(-1)=-2+m-n+c

Substituting x=2 in the given polynomial.

P(2)=2(2)^3+m(2)^2+n(2)+c

P(2)=2(8)+m(4)+2n+c

P(2)=16+4m+2n+c

Now, substitute the values of P(2) and P(-1) in (i), we get

16+4m+2n+c=-2+m-n+c

16+4m+2n+c+2-m+n-c=0

18+3m+3n=0

3m+3n=-18

Divide both sides by 3.

\dfrac{3m+3n}{3}=\dfrac{-18}{3}

m+n=-6

Hence proved.

7 0
3 years ago
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