Question

What is the point-slope form of a line that has a slope of –4 and passes through point (–3, 1)?

Answer 1

Answer:

y - 1 = - 4(x + 3)

Step-by-step explanation:

The equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

Here m = - 4 and (a, b) = (- 3, 1), hence

y - 1 = - 4(x - (- 3)), thus

y - 1 = - 4(x + 3) ← in point- slope form

Answer 2

Answer:

$y-1=-4(x+3)$

Step-by-step explanation:

Given: A line has a slope of -4 and the line passes through a point $(-3, 1)$.

To find: The point-slope form of this line.

Solution:

We know, the point-slope form of a line can be given as

$y-y_{1}=m(x-x_{1} )$

Here, $m$ is the slope of the line, and $(x_{1}, y_{1})$ is the point through which it passes.

The slope of the line is -4, and the point is $(-3, 1)$.

So, $m=-4$, $x_{1} =-3$, and $y_{1} =1$.

Now, putting the values in the equation, we get

$y-1=-4(x-(-3))$

$y-1=-4(x+3)$

Therefore, the point-slope form of the line is $y-1=-4(x+3)$.