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Leto [7]
3 years ago
11

On a coordinate plane, a square and a point are shown. The square has points R prime (negative 8, 1), S prime (negative 4, 1), T

prime (negative 4, negative 3), and U prime (negative 8, negative 3). Point S is at (3, negative 5). Square RSTU is translated to form R'S'T'U', which has vertices R'(–8, 1), S'(–4, 1), T'(–4, –3), and U'(–8, –3). If point S has coordinates of (3, –5), which point lies on a side of the pre-image, square RSTU? (–5, –3) (3, –3) (–1, –6) (4, –9)
Mathematics
2 answers:
trapecia [35]3 years ago
8 0

Answer:

i believe its C (-1,-6)

Step-by-step explanation:

edge 2020

VladimirAG [237]3 years ago
7 0

Answer:

(–1, –6)

Step-by-step explanation:

Given that S(3, –5) was translated to S'(–4, 1), the transformation rule is (x-7, y+6). Then, the coordinates of square RSTU are:

R'(–8, 1) -> (-8+7, 1-6) -> R(-1, -5)

S'(–4, 1) -> (-4+7, 1-6) -> S(3, -5)

T'(–4, –3) -> (-4+7, -3-6) -> T(3, -9)

U'(–8, –3) -> (-8+7, -3-6) -> U(-1, -9)

The point (–1, –6) lies on the segment RU

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Answer:

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Step-by-step explanation:

To find the midpoint, add the x coordinates and divide by 2 and then add the y coordinates and divide by 2

x:  (-1+2)/2 = 1/2=.5

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Step-by-step explanation:

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6 0
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motikmotik
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3 years ago
A student is asked to find the length of the hypotenuse of a right triangle. The length of one leg is 32
zavuch27 [327]

Hypotenuse =39cm of right angle triangle! .

<u>Step-by-step explanation:</u>

Here we have , A student is asked to find the length of the hypotenuse of a right triangle. The length of one leg is 32  centimeters, and the length of the other leg is 25 centimeters. The student incorrectly says that the  length of the hypotenuse is 7.5 centimeters. We need to find:

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We have , One length as 32 cm and other as 25 cm , as

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By Pythagoras Theorem ,

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