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noname [10]
3 years ago
8

Research shows that a passive close to a cover letter leads to more interviews. Please select the best answer from the choices p

rovided T F
Computers and Technology
2 answers:
Vilka [71]3 years ago
8 0

Answer:

The answer is False just took the test.

Explanation:

Alchen [17]3 years ago
6 0
The answer is False.

According to research, a passive close doesn't lead your cover letter to have more interviews. In writing the closing part of your cover letter, it is easy to have a passive sentence but it sounds like less confidence to the employer. The last part of the cover letter should contain strong content to give an impression to the person who reads.
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What is the big-O performance estimate of the following function?
larisa [96]

Answer:

The time complexity of the code is O(log₇n).

Explanation:

The i is updated by 7*i.On each iteration i is multiplied by 7.So on finding the time complexity of the code given above it will come out to  be log base 7.

When we divide the input by 2 the time complexity is log base 2.

So on dividing it by 7 we get the time complexity of log base 7.

8 0
3 years ago
Read 2 more answers
Can u please help me solve this
azamat

Alice has twice as many pencils as Cara. Leon has three more pencils than Alice. The three children have a total of 58 pencils.

<h3>What are the no. of pencils?</h3>

The no. of pencils are there totally as the 11.

Read more about the basic maths:

brainly.com/question/19493296

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4 0
2 years ago
What is the legal right granted to all authors and artists that gives them sole ownership and use of their words, software, pict
ICE Princess25 [194]

Answer:

copyright

Explanation:

3 0
3 years ago
Q10: Putting it all together (0.75 points) Here, we'll update the values in dictionary, storing the output in a dictionary calle
Molodets [167]

Answer:

# Code in Python

dictionary={'A':1,'B':2,'C':3,'D':4}

other_dictionary={}

for keys in dictionary:

if dictionary[keys]&1==1:

temp=dictionary[keys]*dictionary[keys]-10*10

other_dictionary[keys]=temp

else:

other_dictionary[keys]=dictionary[keys]

print(other_dictionary)  

assert other_dictionary

Explanation:

  • Initialize a sample example dictionary  and other_dictionary.
  • Do a binary comparision for checking odd number .
  • Update the the value stored in the dictionary to store the squared difference of the original value and '10'.
  • For even: store the original value (from dictionary).
4 0
3 years ago
The shapes of AND, OR, and NOR gates have something in common. What is it and why do you think they share that feature?
irina1246 [14]
There're all conjunctions.

You can seperate them in sentences after a comma for a run-on sentence.
4 0
2 years ago
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