For number 3 I believe the answer is A\
Change priority from the Details tab. Press Ctrl + Shift + Esc to start Task Manager. Go to the Details tab, right-click the desired process, and choose Set priority and select any value that you want.
Answer:
Rewrite the Espresso Counter program to Swap or interchange any two rows of the output. Copy and paste just the interchanged parts of the code. Compile and run the modified program. Copy and paste the new user interface output. Add a new row to the Espresso Counter user interface. Describe your modifications. Compile and run the new program. Copy and paste
1. Your modifications
2. Snapshots of your new counter interface.
Answer:
The Statement is True.
Explanation:
Public Relations is the term referred to simply building of relations with the public. The strength of the relation describes how strong or weak is the relation of an individual or an organization with the general public. There could be good or poor public relations. Good Public relations are the intangible assets of a company. The statement written in the question tells us about this intangible assets gaining. Public relations strives to foster goodwill between a client and audience. There is always a relation between the company and the consumers’ of company’s product. Here client is considered as the Company and audience is considered as the consumer of the company’s product. So public relations is a way to promote goodwill between the client and the audience. Good public relations will create satisfied customers that would play a part in fostering the goodwill of the company. So there is a direct relation between the good public relations and goodwill of the company.
Answer:
Function sparse code is
def sparse(a):
rl = []
cl = []
for i in range(0,len(a)):
rl.append(a[i][1])
cl.append(a[i][2])
r = max(rl)
c = max(cl)
s = []
k = 0
for i in range(0,r+1):
s.append([])
for j in range(0,c+1):
if (i==a[k][1]) & (j == a[k][2]):
s[i].append(a[k][0])
k = k+1
else:
s[i].append(0)
return s
def main():
k = sparse([[3,1,2],[4,5,3]])
print(k)
if __name__ == '__main__':
main()
Explanation:
Please see attachment for output
