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Alexus [3.1K]
3 years ago
14

Are the arcs below congruent?

Mathematics
2 answers:
asambeis [7]3 years ago
8 0

Answer:

B

You do not have enough information to solve the question.

astraxan [27]3 years ago
7 0

Answer:

A

Step-by-step explanation:

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ruslelena [56]

Answer:

a) = 4/9              b) -20/21

c) -77/6              d) 39/22

Step-by-step explanation:

4 0
2 years ago
Evaluate the expression when z= -5 <br> 100 divided (-z2)
lilavasa [31]

Answer:the anwser is 4

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Plzz show workings while giving the answer​
sukhopar [10]

Answer:

\huge\boxed{\sf 4\ minutes\ 1.5\ seconds}

Step-by-step explanation:

3 minutes 59.1 seconds = (3*60) + 59.1 seconds = 180 + 59.1 seconds

=> 239.1 seconds

\rule[225]{225}{2}

4 minutes 3.8 seconds = (4*60) + 3.8 seconds = 240 + 3.8 seconds

=> 243.8 seconds

\rule[225]{225}{2}

4 minutes 1.6 seconds = (4*60) + 1.6 seconds = 240 + 1.6 seconds

=> 241.6 seconds

\rule[225]{225}{2}

Mean = Sum of data / No. of Data

Mean = 239.1 + 243.8 + 241.6 / 3

Mean = 724.5 / 3

Mean = 241.5 seconds

<u>In Minutes and Seconds:</u>

= 241.5 / 60 = 4.025 minutes

= 4 minutes + 0.025 minutes

= 4 minutes + (0.025 * 60) seconds

= 4 minutes 1.5 seconds

\rule[225]{225}{2}

Hope this helped!

<h3>~AH1807</h3>

8 0
3 years ago
The measure of an angle formed by two secants intersecting outside the circle equals
sineoko [7]
When two secants (Line A + B<span> and </span>Line C + D) intersect, they form an angle (∠y) equal to:
      ½ (the larger intercepted arc minus<span> the smaller intercepted arc)
</span>
(Make sure to look at the graphic I posted)


5 0
4 years ago
Find the sum of the geometric series 512+256+...+4<br> a) 510<br> b) 1,022<br> c) 1,020<br> d) 1,016
zzz [600]

Answer:

Option C. 1020

Step-by-step explanation:

From the question given above,

512 + 256 +... + 4 =?

We'll begin by calculating the number of terms in the sequence. This can be obtained as follow:

First term (a) = 512

Common ratio (r) = 2nd term / 1st term

Common ratio (r) = 256 /512

Common ratio (r) = 1/2

Last term (L) = 4

Number of term (n) =?

Tₙ = arⁿ¯¹

L = arⁿ¯¹

4 = 512 × (1/2)ⁿ¯¹

Divide both side by 512

4 / 512 = (1/2)ⁿ¯¹

1/128 = (1/2)ⁿ¯¹

Express 128 in index form with 2 as the base

1/2⁷ = (1/2)ⁿ¯¹

(1/2)⁷ = (1/2)ⁿ¯¹

Cancel 1/2 from both side

7 = n – 1

Collect like terms

7 + 1 = n

n = 8

Thus, the number of terms is 8

Finally, we shall determine the sum of the series as follow:

First term (a) = 512

Common ratio (r) = 1/2

Number of term (n) = 8

Sum of 8th term (S₈) = ?

Sₙ = a[1 – rⁿ] / 1 – r

S₈ = 512 [1 – (½)⁸] / 1 – ½

S₈ = 512 [1 – 1/256] ÷ ½

S₈ = 512 [255/256] × 2

S₈ = 2 × 255 × 2

S₈ = 1020

Thus, the sum of the series is 1020.

5 0
3 years ago
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