Answer:
a) = 4/9 b) -20/21
c) -77/6 d) 39/22
Step-by-step explanation:
Answer:the anwser is 4
Step-by-step explanation:
Answer:

Step-by-step explanation:
3 minutes 59.1 seconds = (3*60) + 59.1 seconds = 180 + 59.1 seconds
=> 239.1 seconds
![\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Crule%5B225%5D%7B225%7D%7B2%7D)
4 minutes 3.8 seconds = (4*60) + 3.8 seconds = 240 + 3.8 seconds
=> 243.8 seconds
![\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Crule%5B225%5D%7B225%7D%7B2%7D)
4 minutes 1.6 seconds = (4*60) + 1.6 seconds = 240 + 1.6 seconds
=> 241.6 seconds
![\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Crule%5B225%5D%7B225%7D%7B2%7D)
Mean = Sum of data / No. of Data
Mean = 239.1 + 243.8 + 241.6 / 3
Mean = 724.5 / 3
Mean = 241.5 seconds
<u>In Minutes and Seconds:</u>
= 241.5 / 60 = 4.025 minutes
= 4 minutes + 0.025 minutes
= 4 minutes + (0.025 * 60) seconds
= 4 minutes 1.5 seconds
![\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Crule%5B225%5D%7B225%7D%7B2%7D)
Hope this helped!
<h3>
~AH1807</h3>
When two secants (Line A + B<span> and </span>Line C + D) intersect, they form an angle (∠y) equal to:
½ (the larger intercepted arc minus<span> the smaller intercepted arc)
</span>
(Make sure to look at the graphic I posted)
Answer:
Option C. 1020
Step-by-step explanation:
From the question given above,
512 + 256 +... + 4 =?
We'll begin by calculating the number of terms in the sequence. This can be obtained as follow:
First term (a) = 512
Common ratio (r) = 2nd term / 1st term
Common ratio (r) = 256 /512
Common ratio (r) = 1/2
Last term (L) = 4
Number of term (n) =?
Tₙ = arⁿ¯¹
L = arⁿ¯¹
4 = 512 × (1/2)ⁿ¯¹
Divide both side by 512
4 / 512 = (1/2)ⁿ¯¹
1/128 = (1/2)ⁿ¯¹
Express 128 in index form with 2 as the base
1/2⁷ = (1/2)ⁿ¯¹
(1/2)⁷ = (1/2)ⁿ¯¹
Cancel 1/2 from both side
7 = n – 1
Collect like terms
7 + 1 = n
n = 8
Thus, the number of terms is 8
Finally, we shall determine the sum of the series as follow:
First term (a) = 512
Common ratio (r) = 1/2
Number of term (n) = 8
Sum of 8th term (S₈) = ?
Sₙ = a[1 – rⁿ] / 1 – r
S₈ = 512 [1 – (½)⁸] / 1 – ½
S₈ = 512 [1 – 1/256] ÷ ½
S₈ = 512 [255/256] × 2
S₈ = 2 × 255 × 2
S₈ = 1020
Thus, the sum of the series is 1020.