PEMDAS. parenthesis, exponents, multiple or divide (whichever come first from left to right), add or subtract (whichever comes first from left to right)
So first do stuff in parenthesis.
Then do divide because thats next on the list and it happens earlier than the multiply one.
So, A
Answer:
One variable equation that is (4800/x) represents percentage of Emily's dinner fat intake compared to total daily allowance of x gram.
Step-by-step explanation:
lets assume the variable for total daily allowance
lets say total daily allowance of fat = x grams
Fat consumed at dinner = 48 grams
Fat consumed at dinner in percentage = (Fat consumed at dinner/total daily allowance of fat) × 100
= (48 grams/x grams)×100=(4800/x)%
so (4800/x)%
So one variable equation that is (4800/x) represents percentage of Emily's dinner fat intake compared to total daily allowance of x gram.
lets take one example
lets says total daily allowance of fat for Emily = 100gm
so from derived equation that is 4800/x , we can get required percentage by putting x = total daily allowance of fat = 100gm
=4800/100 = 48%.
you can change value of variable x according to total daily allowance and get the required dinner intake percentage by equation 4800/x.
Answer:
probability that the other side is colored black if the upper side of the chosen card is colored red = 1/3
Step-by-step explanation:
First of all;
Let B1 be the event that the card with two red sides is selected
Let B2 be the event that the
card with two black sides is selected
Let B3 be the event that the card with one red side and one black side is
selected
Let A be the event that the upper side of the selected card (when put down on the ground)
is red.
Now, from the question;
P(B3) = ⅓
P(A|B3) = ½
P(B1) = ⅓
P(A|B1) = 1
P(B2) = ⅓
P(A|B2)) = 0
(P(B3) = ⅓
P(A|B3) = ½
Now, we want to find the probability that the other side is colored black if the upper side of the chosen card is colored red. This probability is; P(B3|A). Thus, from the Bayes’ formula, it follows that;
P(B3|A) = [P(B3)•P(A|B3)]/[(P(B1)•P(A|B1)) + (P(B2)•P(A|B2)) + (P(B3)•P(A|B3))]
Thus;
P(B3|A) = [⅓×½]/[(⅓×1) + (⅓•0) + (⅓×½)]
P(B3|A) = (1/6)/(⅓ + 0 + 1/6)
P(B3|A) = (1/6)/(1/2)
P(B3|A) = 1/3
Simple,
1/2 of 60
re-write it as 0.5 of 60 aka 0.5*60
which is 0.5*60=30
Do the same with 1/2 of 24.
0.5 of 24
0.5*24=12.
Thus, it's not the same because they are different numbers and different number give you different answers.
