Work out the volume of this sphere 4.7cm
1 answer:
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Function A: 
. Vertical asymptotes are in the form x=, and they are a vertical line that the function approaches but never hits. They can be easily found by looking for values of <em>x</em> that can not be graphed. In this case, <em>x</em> cannot equal 0, as we cannot divide by 0. Therefore <em>x</em>=0 is a vertical asymptote for this function. The horizontal asymptote is in the form <em>y</em>=, and is a horizontal line that the function approaches but never hits. It can be found by finding the limit of the function. In this case, as <em>x</em> increases, 1/<em>x</em> gets closer and closer to 0. As that part of the function gets closer to 0, the overall function gets closer to 0+4 or 4. Thus y=4 would be the horizontal asymptote for function A.
Function B: From the graph we can see that the function approaches the line x=2 but never hits. This is the vertical asymptote. We can also see from the graph that the function approaches the line x=1 but never hits. This is the horizontal asymptote.
Function B: From the graph we can see that the function approaches the line x=2 but never hits. This is the vertical asymptote. We can also see from the graph that the function approaches the line x=1 but never hits. This is the horizontal asymptote.
Answer:
p = 16
Step-by-step explanation:
Given p is directly proportional to (q + 2)² then the equation relating them is
p = k(q + 2)² ← k is the constant of proportion
To find k use the condition when q = 1, p = 1
1 = k(1 + 2)² = k × 3² = 9k ( divide both sides by 9 )
= k
p = (q + 2)² ← equation of proportion
When q = 10 , then
p = × (10 + 2)² =
× 12² =
× 144 = 16