Ask question

Ask question

All categories

Lubov Fominskaja [6]

3 years ago

12

Given line m is parallel to line n. What theorem or postulate justifies the statement? ∠1 ≅ ∠4 Corresponding angles postulate Al

ternate interior angle theorem Linear Pair postulate Vertica

1 answer:

Andrew [12]3 years ago

7 0

Answer:

corresponding angles postulate

Step-by-step explanation:

just took the test ;)

You might be interested in

Can someone help me please

Vera_Pavlovna [14]

Answer:

B) Y = 5x - 10

Step-by-step explanation:

m = y2-y1 / x2-x1

Hope this helps. Pls give brainliest.

6 0

3 years ago

In the recursive formula an = an−1 + 5, the value of the previous term is represented by

den301095 [7]

Step-by-step explanation:

In the recursive formula an = an−1 + 5

$a_n = a_{n-1}+5$

Suppose if a_5 is the nth term then previous term is a_4

To get the previous term we need to subtract 1 from the n

So a_n is the nth term

$a_{n-1}$ is the previous term

Here 5 represents the common difference between two terms

So value of previous term is represented by

$a_{n-1}$

Answer : $a_{n-1}$

6 0

3 years ago

Micaela is 2 years older than Sam. In 4 years, the sum of their ages will be 40. How old is Micaela now? Describe and fix any er

Verdich [7]

Answer:

Micaela is 17

Step-by-step explanation:

s+2=m

(s+2+4)+(s+4)=40

(s+6)+(s+4)=40

2s+10=40

40-10=30

2s=30

30/2= 15

s=15

{s+2=m}

15+2=m

m=17

5 0

3 years ago

Read 2 more answers

What is the slope of the line that passes through the points (8, 2) and (9,3)? Write

Stella [2.4K]

Answer:

1

Step-by-step explanation:

The formula for slope is [ y2-y1/x2-x1 ].

3-2/9-8

1/1

1

Best of Luck!

5 0

2 years ago

Find a positive number for which the sum of it and its reciprocal is the smallest (least) possible. Let x be the number and let

Allisa [31]

Answer:

$S(x) = x + \frac{1}{x}$ --- Objective function

Interval = $\{x:x=1\}$

Step-by-step explanation:

Given

Represent the number with x

The required sum can be represented as:

$x + \frac{1}{x}$

Hence, the objective function is:

$S(x) = x + \frac{1}{x}$

To get the the interval, we start by differentiating w.r.t x

<em>Using first principle, this gives:</em>

$S'(x) = 1 - \frac{1}{x^2}$

Equate S'(x) to 0 in order to solve for x

$0 = 1 - \frac{1}{x^2}$

Subtract 1 from both sides

$0 -1 = 1 -1 - \frac{1}{x^2}$

$-1 = - \frac{1}{x^2}$

Multiply both sides by -1

$1 = \frac{1}{x^2}$

Cross Multiply

$x^2 * 1 = 1$

$x^2 = 1$

Take positive square root of both sides because x is positive

$\sqrt{x^2} = \sqrt{1$

$x = 1$

Representing x using interval notation, we have

Interval = $\{x:x=1\}$

To get the smallest sum, we substitute 1 for x in $S(x) = x + \frac{1}{x}$

$S(1) = 1 + \frac{1}{1}$

$S(1) = 1 + 1$

$S(1) = 2$

<em>Hence, the smallest sum is 2</em>

3 0

3 years ago