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konstantin123 [22]
3 years ago
5

Please help! 1 question! 50 points! Show your work!

Mathematics
1 answer:
KatRina [158]3 years ago
7 0

Answer:

  \dfrac{2x}{3a^2}

Step-by-step explanation:

\dfrac{3a^4b}{2x}\cdot\dfrac{4x^2}{9a^6b}=\dfrac{3\cdot 4}{2\cdot 9}a^{4-6}b^{1-1}x^{2-1}=\dfrac{2x}{3a^2}

The applicable rules of exponents are ...

  • (a^b)(a^c) = a^(b+c)
  • a^-b = 1/a^b
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