3 years ago

Please help! 1 question! 50 points! Show your work!

Mathematics

1 answer:

KatRina [158]3 years ago

7 0

Answer:

$\dfrac{2x}{3a^2}$

Step-by-step explanation:

$\dfrac{3a^4b}{2x}\cdot\dfrac{4x^2}{9a^6b}=\dfrac{3\cdot 4}{2\cdot 9}a^{4-6}b^{1-1}x^{2-1}=\dfrac{2x}{3a^2}$

The applicable rules of exponents are ...

(a^b)(a^c) = a^(b+c)
a^-b = 1/a^b

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