Answer:
If i have three moles of a gas at a pressure of 5.6 atm and a volume of 3 liters, what is the temperature ?
We have the following data:
n (number of moles) = 3 moles
P (pressure) = 5.6 atm
V (volume) = 12 L
T (temperature) = ? (in Kelvin)
R (gas constant) = 0.082 atm.L / mol.K
We apply the data above to the Clapeyron equation (gas equation), let's see:
Answer:
The temperature is approximately 205 Kelvin
Answer:
$1.70 per share
Step-by-step explanation:
37.90-36.20=1.70
Hello,
1) false
2)True
3)False 24g^4+18g²=6g²(4g²+3)
4)True
Answer:
Step-by-step explanation:
4x+6+3x+8=28
combine like terms
7x+14=28
subtract 14
7x=14
divide
x=2
if you plug it in you get-
4(2)+6+3(2)+8=
8+6+6+8=12+16=28
thats how you can check. if you want me to explain more i can totally help
The answer would be C because it’s the only fraction that does not equal 0.4
