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Rzqust [24]
3 years ago
13

Write an equation of the line passing through the given point (6,-7) and having the given slope m=-9. Write the final answer in

slope- intercept form.
Mathematics
1 answer:
Ede4ka [16]3 years ago
3 0
Y-(-7)=-9(x-6)
Y+7= -9x+54
Subtract 7 from both sides
Y= -9x+47
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Help pleaseeee
Andreyy89

Answer:

8.3 meters

Step-by-step explanation:

58.1 / 7 =8.3

4 0
3 years ago
Read 2 more answers
Write the point slope form of the equation of the line that passes through the points (-3,2) and (-5,3).
DaniilM [7]

Answer:

The answer would be B i think .

7 0
3 years ago
A pilot flies on a bearing of 160° for 30 miles. The pilot then executes a quick turn and flies another 15 miles at a bearing of
vivado [14]

Answer: 34.65 miles at an angle of 325.39°

Step-by-step explanation:

Ok, the initial position is (0,0)

Then she flies 30 miles at an angle of 160°, if we count the angle counterclokwise from the x-axis, the new position will be:

p = (30*cos(120°), 30*sin(120°))

Then she travels another 15 miles at an angle of 205°, the new position is:

p = (30*cos(120°) + 15*cos(205°), 30*sin(120°) + 15*sin(205°))

p = (-28.59 , 19.64)

If she now travles X miles at an angle Y, we must have that the final position is the point (0,0)

this means that:

X*cos(Y) = -(-28.59) = 28.59

X*sin(Y) = -19.64

Now, we can find the quotient between those two equations and use that tan(x) = sin(x)/cos(x)

X*(sin(Y))/(X*cos(Y)) = -19.64/28.59

Tg(Y) = -0.69

Y = ATg(-0.69) = -34.61°

If we use only positive angles, this angle is equivalent to:

360° - 34.61° = 325.39°

now lets find the distance:

Xcos(325.39°) = 28.59

X = 28.59/cos(325.39°) = 34.65 miles.

4 0
3 years ago
30 points and brainliest!! HELP NOW
Natasha2012 [34]

Answer:

First question

a = 1 , h = 0 , k = 6 ⇒ third answer

Second question

y = 2x² + 4 ⇒ second answer

Third question

No of the choices correct ⇒ fourth answer

Step-by-step explanation:

First question

∵ f(x) = x² + 6

- It is a quadratic function with general form ax² + bx + c

- Its vertex is (h , k), where h = -b/2a and k = f(h)

∵ a = 1 , b = 0 , c = 6

∴ h = 0/2(1) = 0

∴ f(0) = 0² + 6 = 6

∴ a = 1 , h = 0 , k = 6 ⇒ third answer

Second question

- If the function f(x) translated vertically up  

 by k units, then the new function g(x) = f(x) + k

- If the function f(x) translated vertically down  

 by k units, then the new function g(x) = f(x) – k

∵ y = 2x²

∵ y is shifted 4 units up

∴ k = 4

∴ y + 4 = 2x² + 4

∴ y = 2x² + 4 ⇒ second answer

Third question

∵ y = -2x² + 3

- It is a quadratic equation with general form ax² + bx + c

- It represented graphically by parabola

- If a is positive the parabola opens upward

- If a is negative the parabola opens downward

∵ a = -2

∴ The parabola opens downward

∴ No of the choices correct ⇒ fourth answer

4 0
3 years ago
Someone help 6th grade math i will give brainliest
Soloha48 [4]
The first one is 64. The second one is -64. Third is 10000
8 0
3 years ago
Read 2 more answers
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