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vodomira [7]
3 years ago
12

An aircraft flying at an average speed of 770 km/h takes 15 hours to complete a journey. Find the time taken for the aircraft to

complete at same journey if it's average speed is 660 km/h
Mathematics
2 answers:
Hoochie [10]3 years ago
8 0
We can solve it two ways, we´ll do it via physics:
We know that:
d=vt
d=770km/h*15h
d=11550km
Now at 660km/h:
t=d/v
t=11550km/660km/h
t=17,5h
Math way:
770km/h→15h
660km/h→x
So:
(770*15)/660=x
x=17,5h
inessss [21]3 years ago
4 0
Seventeen hours and fifteen minutes
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​write the logarithm as a sum or difference of logarithms. simplify each term as much as possible. log4(6ab)
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The logarithm written as a sum of logarithm and simplified as much as possible is \frac{1}{2} +log_{4 }3 +  log_{4 }a + log_{4 }b

<h3>Simplifying Logarithms</h3>

From the question, we are to write the given logarithm expression as a sum or difference of logarithms

The given logarithm is

log_{4 }6ab

This can be written as

log_{4 }6 \times a \times b

From one of the rules of logarithm, we have that

log_{x }yz= log_{x }y + log_{x }z

Thus,

log_{4 }6 \times a \times b  becomes

log_{4 }6 + log_{4 }a + log_{4 }b

This can be further simplified into

log_{4 }3 \times 2 + log_{4 }a + log_{4 }b

log_{4 }3 + log_{4 }2 + log_{4 }a + log_{4 }b

If desired, this can be further simplified into

log_{4 }3 + log_{2^{2}  }2 + log_{4 }a + log_{4 }b

log_{4 }3 + \frac{1}{2} log_{2}2 + log_{4 }a + log_{4 }b

log_{4 }3 + \frac{1}{2} (1)+ log_{4 }a + log_{4 }b

\frac{1}{2} +log_{4 }3 +  log_{4 }a + log_{4 }b

Hence, the logarithm written as a sum of logarithm and simplified as much as possible is \frac{1}{2} +log_{4 }3 +  log_{4 }a + log_{4 }b

Learn more on Simplifying logarithms here: brainly.com/question/17851187

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