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vodomira [7]
3 years ago
12

An aircraft flying at an average speed of 770 km/h takes 15 hours to complete a journey. Find the time taken for the aircraft to

complete at same journey if it's average speed is 660 km/h
Mathematics
2 answers:
Hoochie [10]3 years ago
8 0
We can solve it two ways, we´ll do it via physics:
We know that:
d=vt
d=770km/h*15h
d=11550km
Now at 660km/h:
t=d/v
t=11550km/660km/h
t=17,5h
Math way:
770km/h→15h
660km/h→x
So:
(770*15)/660=x
x=17,5h
inessss [21]3 years ago
4 0
Seventeen hours and fifteen minutes
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dmitriy555 [2]

The answer is c. \frac{46}{9}

a. \frac{11}{5}=2.2 (2.2≠5.11) (2.2 is not equal to 5.11)

b. 5\frac{1}{8}=\frac{5}{8} or 0.625 (0.625≠5.11) (0.625 is not equal to 5.11)

c. \frac{46}{9} =5.11 (5.11=5.11) (5.11 is equal to 5.11)

Therefore c is the answer

4 0
3 years ago
Which of the following are one-dimensional and have infinite length?
Alona [7]
Out of the choices, the entities with only one dimension and have infinite length are the line and ray. The line extends to both sides while the ray is restricted by an endpoint on one side but can extend infinitely to the other side. The answers are therefore letter D and F. 
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3 years ago
Read 2 more answers
Show tan(???? − ????) = tan(????)−tan(????) / 1+tan(????) tan(????)<br> .
anyanavicka [17]

Answer:

See the proof below

Step-by-step explanation:

For this case we need to proof the following identity:

tan(x-y) = \frac{tan(x) -tan(y)}{1+ tan(x) tan(y)}

We need to begin with the definition of tangent:

tan (x) =\frac{sin(x)}{cos(x)}

So we can replace into our formula and we got:

tan(x-y) = \frac{sin(x-y)}{cos(x-y)}   (1)

We have the following identities useful for this case:

sin(a-b) = sin(a) cos(b) - sin(b) cos(a)

cos(a-b) = cos(a) cos(b) + sin (a) sin(b)

If we apply the identities into our equation (1) we got:

tan(x-y) = \frac{sin(x) cos(y) - sin(y) cos(x)}{sin(x) sin(y) + cos(x) cos(y)}   (2)

Now we can divide the numerator and denominato from expression (2) by \frac{1}{cos(x) cos(y)} and we got this:

tan(x-y) = \frac{\frac{sin(x) cos(y)}{cos(x) cos(y)} - \frac{sin(y) cos(x)}{cos(x) cos(y)}}{\frac{sin(x) sin(y)}{cos(x) cos(y)} +\frac{cos(x) cos(y)}{cos(x) cos(y)}}

And simplifying we got:

tan(x-y) = \frac{tan(x) -tan(y)}{1+ tan(x) tan(y)}

And this identity is satisfied for all:

(x-y) \neq \frac{\pi}{2} +n\pi

8 0
3 years ago
In a movie theater, the first row contains 3 seats, the second row contains 6 seats, the third row contains 9 seats, and the fou
yanalaym [24]

Answer:It's an arithmetic sequence with a common difference, d, = 4

A1 = 8

A2 = 8+4 = 12

A3 = 12+4 = 16   = 8+4(3-1) = 8+4(2) = 8+8

AN = A1 + d(N-1)

AN = 8 +4(N-1)  =  the Nth term in the sequence

Step-by-step explanation: hoped it helped

7 0
2 years ago
Plz guys help i need asap<br> its part b im stuck
aleksklad [387]

Answer:

a.2nd quarter with 9 goals

b. 4.8 goals

c. 4 goals

Step-by-step explanation:

a. The mode is defined as the most appearing data point or the data point with the highest frequency..

From our data(for away goals):

  • 1st quarter-2
  • 2nd quarter-9
  • 3rd quarter-7
  • 4th quarter-4

Hence, the 2nd quarter has the mode for away goals with 9 goals.

b. Mean is defined as the average of a set of data points.

#We calculate the totals goals per quarter, sum over all quarters then divide by the number of games, 10:

\bar x=\frac{1}{n}\sum{x_i}\\1^{st }_g=Away+Home=5+2=7\\\\2^{nd}_g=Away+Home=4+9=13\\\\3^{rd}_g=Away+Home=8+7=15\\\\4^{th}_g=Away+Home=9+4=13\\\\\bar x=\frac{1}{n}\sum{x_i}=\frac{1}{10}(7+13+15+13)=4.8

Hence, the mean number of goals per quarter is 4.8 goals

c. To find the number of more home goals than away goals, we subtract from their summations as:

g_m=\sum{g_h}-\sum{g_a}\\\\=(5+4+8+9)-(2+9+7+4)\\\\=26-22\\\\=4

Hence, there are 4 more home goals than away goals.

4 0
3 years ago
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