Are you sure the question is correct? From a list of integers, if you pick one number, it's guaranteed to be an integer...
Surely there's a condition that you haven't mentioned?
Represent these consecutive numbers (assuming that they are all integers):
x
x+1
x+2
x+3
x+4
x+5
and so on
x+8
x+9 is the tenth number. x+9 = 10, so x = 9.
Think of it this way: there are 10 consecutive numbers, and the last one is 10.
Working backwards, we get the sequence 10, 9, ... 3, 2, 1.
The sum of such an arith sequence is equal to the count of the numbers times the average of the first and last terms:
sum here = 10(1+10)/2 = 5(11) = 55 (answer)
Answer: X = kuv/ (u+v)
that means that x(u+v)/(uv) = k, a constant. so you want x such that,
x(3+3)/(3*3) = 3(3+1)/(3*1)
x=6
The answer is a² + 6. "Sum of a squared and 6" means you square a value and then add 6 to it.
Answer:
subject
Step-by-step explanation:
subject is a noun (person, place or thing)
verb is doing something *example: running
object is a thing *example: apple
conjunction is a word used to connect sentences *example: but
