Answer:
First we need to name some of the variables we are given:n = 38 the sample sizex = 6.88 the sample mean = 1.86 the population standard deviationWe need to find a 90% confidence interval for the mean price per 100 lbs of watermelon: = 1-.90 = .10/2 = .05z(/2) = -1.64-z(/2) = 1.64This can give us a probability expression:P(-1.645 < z < 1.645) = .90The margin of error is calculated with the formula: E = z(/2)(/√n)E = 1.645(1.86/√38) = $.4963(300) = $148.89 Then to calculate the upper and lower limit we add and subtract E from x:lower limit = 6.88 - .4963 = $7.38(300) = $2214upper limit = 6.88 + .4963 = $6.38(300) = $1914Note: We multiply the E, upper and lower limits by 300 because 15 tons is 30000lbs and we need the price per 100 lbs, so we divide 30000/100 and get 300.
Step-by-step explanation:
The answer to the problem is A
Answer:
The hourly pay for the lifeguards in 2001 was of $6.31.
Step-by-step explanation:
The hourly pay, in dollars, in t years after 1995, is given by the following equation:
What was the hourly pay for the lifeguards in 2,001?
2001 is 2001 - 1995 = 6 years after 1995. So this is P(6).
The hourly pay for the lifeguards in 2001 was of $6.31.
Answer:
2/27
Step-by-step explanation:
In the question we have:
4 snickers
2 packages of M&M's
3 Butterfingers.
Total number of candies in the Halloween bag = 9
Probability of selecting some M&M's and putting them back = 2/9
Probability of selecting a Butter finger = 3/9
Therefore, the probability of selecting some M&M's, putting them back, and then selecting a Butterfinger =
Probability of selecting some M&M's and putting them back × Probability of selecting a Butter finger
2/9 × 3/9
= 6/ 81
= 2/27
Hi there!
We can begin by making each fraction have a common denominator:
If we make each have a common denominator of ab, we get:
Simplify:
Multiply both sides by ab:
Move b to the opposite side:
Factor out b:
Divide by (ac - 1):
