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Tems11 [23]
3 years ago
15

The expression means the product of 5 and the difference of three times r minus 10. If r = 4, the value of the expression is .

Mathematics
1 answer:
Morgarella [4.7K]3 years ago
4 0

Answer:

10

Step-by-step explanation:

"three times r" = 3r

"three times r minus ten" = 3r - 10

"product of 5 and the difference of three times r minus ten"

= 5 (3r - 10)

given that r = 4,

the expression becomes

5 (3r - 10)

= 5 [3(4) - 10]

= 5 [12 - 10]

= 5 (2)

= 10

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3 years ago
A is an m×n matrix.Check the true statements below:A. The kernel of a linear transformation is a vector space.B. If the equation
Bess [88]

Answer:

Results are (1) True. (2) False. (3) False. (4) True. (5) True. (6) True.

Step-by-step explanation:

Given A is an m\times n matrix.  Let T :U\to V  be the corresponding linear transformationover the field F and \theta be identity vector in V. Now if x\in Ker( T)\implies T(x)=\theta.

(1) The kernel of a linear transformation is a vector space : True.

Let x,y\in Ker( T), then,

T(x+y)=T(x)+T(y)=\theta+\theta=\theta\impies x+y\in Ker( T)

hence the kernel is closed under addition.

Let \lambda\in F, x\in Ker( T), then

T(\lambda x)=\lambda T(x)=\lambda\times \theta=\theta

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Finally, fore all vectors u\in U,

T(\theta)=T(\theta+(-\theta))=T(\theta)+T(-\theta)=T(\theta)-T(\theta)=\theta

\implies \theta\in Ker(T)

Thus Ker(T) is a subspace.

(2) If the equation Ax=b is consistent, then Col(A) is \mathbb R^m : False

if the equation Ax=b is consistent, then Col(A) must be consistent for all b.

(3) The null space of an mxn matrix is in \mathbb R^m

: False

The null space that is dimension of solution space of an m x n matrix is always in \mathbb R^n.

(4) The column space of A is the range of the mapping x\to Ax

: True.

(5) Col(A) is the set of all vectors that can be written as Ax for some x. : True.

Here Ax will give a linear combination of column of A as a weights of x.

(6) The null space of A is the solution set of the equation Ax=0.

: True

5 0
3 years ago
Anyone help me, please I need help<br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%7Bx%20-%205%7D%20%20%3D%20%208%20%5Csqrt%5B%5
Ilya [14]

Answer:

No Real Solutions.

Step-by-step explanation:

√(x-5)=8√(x-2)

Square on both sides,

(√(x-5))^2=(8√(x-2))^2

or,(x-5)=64(x-2)

or,x-5=64x-128

or,-5+128=64x-x

or,123/63=x

Therefore, x=41/21

If you plug x=41/21 in √(x-5)=8√(x-2) you do not get equals, so the problem has no real solutions.

7 0
3 years ago
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