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harina [27]
3 years ago
12

Solve this equation by using the substitution method. Make sure you show ALL your work.

Mathematics
1 answer:
djverab [1.8K]3 years ago
4 0

Step-by-step explanation:

substitute for y

x+3+4 = -6x

x+ 7 = -6x

7 = -7x

-1 = x

y = -1+3

y = 2

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(b)<br> Using the formula 2T = M + 3K, find the value of K when T = 11 and M = 4.
Sunny_sXe [5.5K]

Answer:

K = 6

Step-by-step explanation:

Plug in what the letter equals to

Equation will look like:

2(11) = 4 + 3k  or  3k + 4 = 2(11)

multiple the 2 by 11 and get 22

3k + 4 = 22 subtract the 4 so it can leave the 3k alone

22 - 4 = 18 now divide 3 from k and do it in the other side

18/3 = 6

so K = 6

4 0
3 years ago
What is 8.072 rounded to the nearest hundredths
OlgaM077 [116]
Hundredths = 7
rounded off = 8.07
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3 years ago
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Triangle ABC is similar to triangle WYZ.
LenaWriter [7]

Answer:

∠B

∠Y

Step-by-step explanation:

we know that

In the right triangle ABC

----> opposite side to angle B divided by the adjacent side to angle B

substitute the values

Remember that

If two triangles are similar, then the corresponding sides are proportional and the corresponding angles are congruent

so

∠A=∠W

∠B=∠Y

∠C=∠Z

4 0
2 years ago
Write two equivalent expressions to represent the area of this rectangle.
Alex777 [14]
5(x-2) or 5x-10 are both correct
3 0
3 years ago
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I roll a fair die twice and obtain two numbers X1= result of the first roll and X2= result of the second roll. Given that I know
azamat

By definition of conditional probability,

P(X_1=4\text{ or }X_2=4\mid X_1+X_2=7)=\dfrac{P((X_1=4\text{ or }X_2=4)\text{ and }X_1+X_2=7)}{P(X_1+X_2=7)}

=\dfrac{P((X_1=4\text{ and }X_1+X_2=7)\text{ or }(X_2=4\text{ and }X_1+X_2=7))}{P(X_1+X_2=7)}

Assuming a standard 6-sided fair die,

  • if X_1=4, then X_1+X_2=7 means X_2=3; otherwise,
  • if X_2=4, then X_1=3.

Both outcomes are mutually exclusive with probability \frac1{36} each, hence total probability \frac2{36}=\frac1{18}.

Of the 36 possible outcomes, there are 6 ways to sum the integers 1-6 to get 7:

(1, 6), (2, 5), (3, 4), (4, 3), (5, 2), (6, 1)

and so a sum of 7 occurs \frac6{36}=\frac16 of the time.

Then the probability we want is

P(X_1=4\text{ or }X_2=4\mid X_1+X_2=7)=\dfrac{\frac1{18}}{\frac16}=\frac13

6 0
3 years ago
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