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marin [14]
3 years ago
13

Which of the following is a radical equation?

Mathematics
2 answers:
weeeeeb [17]3 years ago
8 0

Answer:

D

Step-by-step explanation:

A radical equation persists when a radical includes a variable within it. In this case the x is in the radical, times 7. The rest of the answers do not have a variable in a radical.

slavikrds [6]3 years ago
5 0

Answer:

7 square root x = 14​

Step-by-step explanation:

A radical equation will have the variable inside the radical

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Given that f(x) = x + 3<br> a) Find f(2)
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{ \qquad\qquad\huge\underline{{\sf Answer}}}

Here we go ~

In the above question, it is given that :

\qquad \sf  \boxed{ \sf f(x) =  \frac{x + 3}{2} }

A.) Find f(2) :

\qquad \sf  \dashrightarrow \: f(2) =  \dfrac{2 + 3}{2}

\qquad \sf  \dashrightarrow \: f(2) =  \dfrac{5}{2}

or

\qquad \sf  \dashrightarrow \: f(2) = 0.5

B.) Find { \sf {f}^{-1}(x) } :

\qquad \sf  \dashrightarrow \: let \: y = f (x)

so, we can write it as :

\qquad \sf  \dashrightarrow \: y =  \dfrac{x + 3}{2}

\qquad \sf  \dashrightarrow \: 2y = x + 3

\qquad \sf  \dashrightarrow \: x = 2y - 3

Now, put x = { \sf {f}^{-1}(x) }, and y = x and we will get our required inverse function ~

\qquad \sf  \dashrightarrow \: f {}^{ - 1}(x) = 2x- 3

C.) Find { \sf {f}^{-1}(12) } :

\qquad \sf  \dashrightarrow \: f {}^{ - 1}(12) = 2(12)- 3

\qquad \sf  \dashrightarrow \: f {}^{ - 1}(12) = 36- 3

\qquad \sf  \dashrightarrow \: f {}^{ - 1}(12) = 33

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1 year ago
What does x mean in maths
Nana76 [90]
X is usually the representation for the unknown number.


3 0
3 years ago
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