Answer:
A. y=-1/3x+10
Step-by-step explanation:
Perpendicular gradients(slopes) are negative reciprocals so
m=-1/3 then use the point (6,8) to find the equation of the line
y=mx+b
8=(-1/3)(6)+b
8=-2+b
b=10
y=-1/3x+10
GIVEN :
a = 1/√10 ( 3i + k) and
b = 1/7 ( 2i + 3j - 6k)
TO FIND :
( 2a- b) . [ ( a x b ) x ( a + 2b)]
SOLUTION :
◆Going with the equation given,
( 2a - b) . [ ( a x b ) x ( a + 2b)]
= (2a - b) [( a×b×a) + 2(a×b)×b]
◆BAC - CAB RULE,
A×B×C = B( A.B ) - C(A.B )
= (2a- b ) [ (b (a.a ) - a (a.b ) + 2b ( a.b) -2b (a.b]
Solving further
= (2a - b )(b - 2a)
= -4a.a -b.b
=-5.
Answer:
( 2 - b) . [ ( a x b ) x ( a + 2b)] = -5
Hoped I helped
Answer:
=−14x+18
Step-by-step explanation:
happy to help ya :)
Hello there,
If you are putting 28 on the less than side it is.
Correct
30>28
Incorrect
28>30
Hope this helped!
6-8x=-3x+11
-8x+3x=11-6
-5x=5
x=-1
The first step is to isolate the variable, then you solve. Hope this helps, brainliest if you can.
