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il63 [147K]
4 years ago
15

Hurry hurry plsplslslslslsl?!?!?!?!

Chemistry
2 answers:
photoshop1234 [79]4 years ago
6 0

Answer:

it would increase.

Explanation:

if light is not provided to the producer,the animals rate of death would certainly increase,making the decomposing level faster than normal

user100 [1]4 years ago
4 0

Answer:

The rest of the food chain will not have as much to eat and will decrease in population and the decomposers will grow in population because the rest of the creatures will die and give the decomposers more food

Explanation:

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C. Use Hess's law and the following equations to calculate ΔH for the reaction 4NH3 (g) + 5O2 (g) 4NO(g) + 6H2 O(g). Show your w
Monica [59]

Considering the Hess's Law, the enthalpy change for the reaction is -906.4 kJ/mol.

<h3>Hess's Law</h3>

Hess's Law indicates that the enthalpy change in a chemical reaction will be the same whether it occurs in a single stage or in several stages. That is, the sum of the ∆H of each stage of the reaction will give us a value equal to the ∆H of the reaction when it occurs in a single stage.

<h3>ΔH in this case</h3>

In this case you want to calculate the enthalpy change of:

4 NH₃ + 5 O₂ → 4 NO + 6 H₂O

which occurs in three stages.

You know the following reactions, with their corresponding enthalpies:

Equation 1: 2 N₂ + 6 H₂ → 4 NH₃   ΔH = –183.6 kJ/mol

Equation 2:  2 N₂ + 2 O₂ → 4 NO     ΔH = 361.1 kJ/mol

Equation 3: 2 H₂ + O₂→ 2 H₂O     ΔH = -483.7 kJ/mol

Because of the way formation reactions are defined, any chemical reaction can be written as a combination of formation reactions, some going forward and some going back.

In this case, first, to obtain the enthalpy of the desired chemical reaction you need 4 moles of NH₃ on reactant side and it is present in first equation on product side. So you need to invert the reaction, and when an equation is inverted, the sign of delta H also changes.

Now, 4 moles of NO must be a product and is present in the second equation, so let's write this as such.

Finally, you need 6 moles of H₂O on the product side, so you need to multiply by 3 the third equation to obtain the amount of water that you need. Since enthalpy is an extensive property, that is, it depends on the amount of matter present, since the equation is multiply by 3, the variation of enthalpy also.

In summary, you know that three equations with their corresponding enthalpies are:

Equation 1: 2 4 NH₃ → N₂ + 6 H₂  ΔH = 183.6 kJ/mol

Equation 2:  2 N₂ + 2 O₂ → 4 NO     ΔH = 361.1 kJ/mol

Equation 3: 6 H₂ + 3 O₂→ 6 H₂O     ΔH = -1,451.1 kJ/mol

Adding or canceling the reactants and products as appropriate, and adding the enthalpies algebraically, you obtain:

4 NH₃ + 5 O₂ → 4 NO + 6 H₂O ΔH= -906.4 kJ/mol

Finally, the enthalpy change for the reaction is -906.4 kJ/mol.

Learn more about Hess's law:

brainly.com/question/5976752

brainly.com/question/13707449

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brainly.com/question/6263007

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#SPJ1

7 0
2 years ago
A molecule of glucose is comprised of 6 atoms of carbon, 12 atoms of hydrogen, and 6 atoms of oxygen.
Svetradugi [14.3K]

Answer:

C6H12O6 the third choice

3 0
3 years ago
In the coal-gasification process, carbon monoxide is converted to carbon dioxide via the following reaction: CO (g) H2O (g) CO2
jolli1 [7]

Answer: K_{eq} at  the temperature of the experiment is 0.56.

Explanation:

Moles of  CO = 0.35 mole

Moles of  H_2O = 0.40 mole

Volume of solution = 1.00 L

Initial concentration of CO = \frac{0.35mol}{1.00L}=0.35M

Initial concentration of H_2O = \frac{0.40mol}{1.00L}=0.40M

Equilibrium concentration of CO = \frac{0.19mol}{1.00L}=0.19M

The given balanced equilibrium reaction is,

                      CO(g)+H_2O(g)\rightleftharpoons CO_2(g)+H_2(g)

Initial conc.          0.35 M         0.40 M                  0 M        0M

    At eqm. conc.     (0.35-x) M   (0.40-x) M   (x) M      (x) M

Given:  (0.35-x) = 0.19

x= 0.16 M

The expression for equilibrium constant for this reaction will be,

K_{eq}=\frac{[CO_2]\times [H_2]}{[CO]\times [H_2O]}  

Now put all the given values in this expression, we get :

K_{eq}=\frac{0.16\times 0.16}{(0.35-0.16)\times (0.40-0.16)}

K_{eq}=\frac{0.16\times 0.16}{(0.19)\times (0.24)}=0.56

Thus K_{eq} at  the temperature of the experiment is 0.56.

3 0
3 years ago
Team distillation may be used to separate a mixture of p-nitrophenol and o-nitrophenol. the ortho isomer distills at 93 _c; the
a_sh-v [17]
Para and ortho is actually indicating different name structure of mixture. So if structure is different then boiling/distill/melt temprature will be also different.
6 0
4 years ago
Is SiHCl3 polar or non polar
tiny-mole [99]
The answer is polar.
7 0
3 years ago
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