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4 years ago

5

He access code for a car's security system consists of four digits. the first digit cannot be 8 and the last digit must be even

. how many different codes are available? the number of different codes available is nothing .

1 answer:

Naya [18.7K]4 years ago

7 0

There are 10 total numbers ( 0, 1, 2,3, 4, 5, 6, 7, 8, 9)

The first number cannot be an 8, so it can be 9 different numbers.

The second number can be any of 10 numbers.

The third number can also be any of 10 numbers.

The fourth number can only be even so it can be 0, 2 , 4, 6, 8, so any of 5 numbers.

To find the total combinations, multiply the available choices by each other:

9 x 10 x 10 x 5 = 4,500 different combinations.

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Please help i am stuck and trying not to fail lol. also if you can show work pls

wel

Given:

The figure of rectangle.

To find:

a. The diagonal of the rectangle.

b. The area of the rectangle.

c. perimeter of the rectangle.

Solution:

(a)

In a right angle triangle,

$\sin \theta=\dfrac{Perpendicular}{Hypotenuse}$

$\sin 30=\dfrac{12}{Hypotenuse}$

$\dfrac{1}{2}=\dfrac{12}{Hypotenuse}$

$Hypotenuse=12\times 2$

$Hypotenuse=24$

So, the diagonal of the of the rectangle is 24 units.

(b)

In a right angle triangle,

$\tan \theta=\dfrac{Perpendicular}{Base}$

$\tan 30=\dfrac{12}{Base}$

$\dfrac{1}{\sqrt{3}}=\dfrac{12}{Base}$

$Base=12\sqrt{3}$

Length of the rectangle is 12 and width of the rectangle is $12\sqrt{3}$ . So, the area of the rectangle is:

$Area=length \times width$

$Area=12 \times 12\sqrt{3}$

$Area=144\sqrt{3}$

So, the area of the rectangle is $144\sqrt{3}$ sq. units.

(c)

Perimeter of the rectangle is:

$P=2(length+width)$

$P=2(12+12\sqrt{3})$

$P=24+24\sqrt{3}$

$P\approx 65.57$

Therefore, the perimeter of the rectangle is about 65.57 units.

4 0

3 years ago

Easy math pls help quick will give brainlest

salantis [7]

Answer:

Problem 9: h(1/8) = 5/8

Problem 10: k = -5

Step-by-step explanation:

Problem 9:

$h( \frac{1}{8} ) = 3( \frac{1}{8} ) + \frac{1}{4} = \frac{3}{8} + \frac{2}{8} = \frac{5}{8}$

Problem 10:

$\frac{k - 3}{2} = - 4$

$k - 3 = - 8$

$k = - 5$

8 0

3 years ago

What is 5.6 as a fraction??

Dafna1 [17]

The answer is a mix number 5 and 3/5

4 0

4 years ago

Read 2 more answers

The Dean of the Business School at State University would like to test the hypothesis that no difference exists between the aver

kolbaska11 [484]

Answer:

Paired samples t- test is appropriate for Dean's hypothesis

Step-by-step explanation:

Given Data :

Student 1 2 3 4 5 6 7 8

Marketing 82 86 74 93 90 76 87 100

Finance 76 91 70 79 96 70 85 81

We are supposed to find the test which is appropriate for Dean's hypothesis

We are given the grades of two different subjects for same student

We perform the paired t test because the final grades for the Marketing and Finance is taken for the same student.

So, Option B is correct

Hence Paired samples t- test is appropriate for Dean's hypothesis

8 0

4 years ago

What is the answer to x/3-2=7

Firlakuza [10]

<span> x/3-2=7
---------------------
SImplify
1/3x - 2 = 7
--------------------------
add 2 to each side
1/3x - </span><span><span>2 </span>+ 2 </span>= <span>7 + <span>2
1/3x = 9
------------------------------
Multiply each side by 3
3 * (1/3x) = 3 * 9
x = 27</span></span>

3 0

3 years ago