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3 years ago

5

He access code for a car's security system consists of four digits. the first digit cannot be 8 and the last digit must be even

. how many different codes are available? the number of different codes available is nothing .

1 answer:

Naya [18.7K]3 years ago

7 0

There are 10 total numbers ( 0, 1, 2,3, 4, 5, 6, 7, 8, 9)

The first number cannot be an 8, so it can be 9 different numbers.

The second number can be any of 10 numbers.

The third number can also be any of 10 numbers.

The fourth number can only be even so it can be 0, 2 , 4, 6, 8, so any of 5 numbers.

To find the total combinations, multiply the available choices by each other:

9 x 10 x 10 x 5 = 4,500 different combinations.

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Ipatiy [6.2K]

Answer:

bhhujnejnj

Step-by-step explanation:

8 0

3 years ago

PLEASE HELP ME:<br><br> Find the perimeter of the figure. Round to the nearest tenth.

Ksenya-84 [330]

Answer:

perimeter = 20.9 units

Step-by-step explanation:

perimeter

perimeter = distance around two dimensional shape

= addition of all sides lengths

<h2>perimeter of the figure</h2><h2>= AB+BC+CD+AD</h2>

distance formula:

$d = \sqrt{( x_{2} - x_{1}) {}^{2} + ( y_{2} - y_{1}) {}^{2} }$

<h3>1) distance of AB</h3>

A(-3,0) B(2,4)

x1 = -3 x2 = 2

y1 = 0 y2 = 4

(substitute the values into the distance formula)

$ab = \sqrt{(2 - ( - 3)) {}^{2} + (4 - 0) {}^{2} }$

$ab = \sqrt{5 {}^{2} + 4 {}^{2} }$

$ab = \sqrt{41}$ AB = 6.4 units

<h3>2) distance of BC</h3>

B(2,4) C(3,1)

x1 = 2 x2 = 3

y1 = 4 y2 = 1

$bc = \sqrt{(3 - 2) {}^{2} + (1 - 4) {}^{2} }$

$bc = \sqrt{1 {}^{2} + ( - 3) {}^{2} }$

$bc = \sqrt{10}$

BC = 3.2 units

<h3>3) distance of CD</h3>

C(3,1) D(-4,-3)

x1 = 3 x2 = -4

y1 = 1 y2 = -3

$cd = \sqrt{( - 4 - 3) {}^{2} + ( - 3 - 1)) {}^{2} }$

$cd = \sqrt{( - 7) {}^{2} + ( - 4 ){}^{2} }$

$cd = \sqrt{65}$

CD = 8.1 units

<h3>4) distance of AD</h3>

A(-3,0) D(-4,-3)

x1 = -3 x2 = -4

y1 = 0 y2 = -3

$ad = \sqrt{( - 4 - ( - 3)) {}^{2} + ( - 3 - 0) {}^{2} }$

$ad = \sqrt{( - 1) {}^{2} + ( - 3) {}^{2} }$

$ad = \sqrt{10}$

AD = 3.2 units

<h2>perimeter of figure</h2>

= AB+BC+CD+AD

= 6.4 + 3.2 + 8.1 + 3.2

= 20.9 units

8 0

3 years ago

True or False: The angle opposite a side length of 6 cm in a triangle is larger than an angle opposite a side length of 7 cm in

kipiarov [429]

Answer:

False

Step-by-step explanation:

The angle opposite the longest side is the largest

The angle opposite the shortest side is the smallest

So the angle opposite 6 cm is smaller than the angle opposite 7 cm

3 0

2 years ago

Read 2 more answers

For the given function, x can have what value?

Lyrx [107]

Answer:

x cannot be -4,-3, or 13

x can be anything else

Step-by-step explanation:

There are infinitely many values x can take where the relation above will be a function.

For it to be a function, you just need to make sure each x is only assigned one y value.

So x couldn't be -4 because it would by assigned to y=2 and y=0.

x couldn't be -3 because it would be assigned to y=1 and y=0.

x couldn't be 13 because it would be assigned to y=5 and y=0.

So as long as x is not chosen to be -4,-3, or 13 your relation here is a function.

5 0

3 years ago

Which are the solutions of the quadratic equation? x2 = –5x – 3 –5, 0 StartFraction negative 5 minus StartRoot 13 EndRoot Over 2

boyakko [2]

<u>Given</u>:

The quadratic equation is $x^{2}=-5 x-3$

We need to determine the solutions of the quadratic equation.

<u>Solution</u>:

Let us solve the equation to determine the value of x.

Adding both sides of the equation by 5x and 3, we get;

$x^{2}+5 x+3=0$

The solution of the equation can be determined using quadratic formula.

Thus, we get;

$x=\frac{-5 \pm \sqrt{5^{2}-4 \cdot 1 \cdot 3}}{2 \cdot 1}$

$x=\frac{-5 \pm \sqrt{25-12}}{2 }$

$x=\frac{-5 \pm \sqrt{13}}{2 }$

Thus, the two roots of the equation are $x=\frac{-5 + \sqrt{13}}{2 }$ and $x=\frac{-5- \sqrt{13}}{2 }$

Hence, the solutions of the equation are $x=\frac{-5 + \sqrt{13}}{2 }$ and $x=\frac{-5- \sqrt{13}}{2 }$

6 0

3 years ago

Read 2 more answers