Answer:
r = <u>26</u>
Step-by-step explanation:
If youre usinf substitution to find a solution what happens when u get 0=0
1 answer:
You might be interested in
Given:
The increase in pressure P is the linear function of the depth d.
The cost of dinner is $300 and $10 per students.
To find:
The initial value and rate of change and their interpretation.
Find the cost function C where n is the number of students.
Solution:
The slope intercept form of a linear function is
...(i)
where, m is rate of change and b is y-intercept or initial value.
We have,
...(ii)
From (i) and (ii), we get
The initial value is 14.7. It means, the pressure at sea level is 14.7 pounds psi.
Rate of change is 0.445. It means, the pressure is increasing by 0.445 pounds psi for every feet.
The cost of dinner is $300 and $10 per students.
Let C(n) be the total cost for dinner and n be the number of students.
Fixed cost = $300
Additional cost for 1 student = $10
Additional cost for n student = $10n
Now,
Total cost = Fixed cost + Additional cost
Therefore, the required cost function is .
Answer:
Let x be the width of the compartment,
Then according to the question,
The length of the compartment = x + 2
And the depth of the compartment = x -1
Thus, the volume of the compartment,
But, the volume of the compartment must be 8 cubic meters.
⇒
⇒
⇒
If and if
But, width can not be the complex number.
Therefore, width of the compartment = 2 meter.
Length of the compartment = 2 + 2 = 4 meter.
And, Depth of the compartment = 2 - 1 = 1 meter.
Since, the function that shows the volume of the compartment is,
When we lot the graph of that function we found,
V(x) is maximum for infinite.
But width can not infinite,
Therefore, the maximum value of V(x) will be 8.
Let 
and 
be the sides of the rectangle. The perimeter is given to be 500m, so we are maximizing the area function 
subject to the constraint 
.
From the constraint, we find
so we can write the area function independently of:
Differentiating and setting equal to zero, we find one critical point:
which means
, so in fact the largest area is achieved with a square fence that surrounds an area of 
.
From the constraint, we find
so we can write the area function independently of
Differentiating and setting equal to zero, we find one critical point:
which means