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Nat2105 [25]
3 years ago
14

(b) Fatima starts a phone call at 18:32 The phone call finishes at 19:16

Mathematics
1 answer:
VMariaS [17]3 years ago
6 0
44 minutes, 28+16 = 44
There is 60 minutes in an hour
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If he = 7x -27 find the value of x
Amiraneli [1.4K]

\\ \sf\longmapsto 7x-27=1

\\ \sf\longmapsto 7x=1+27

\\ \sf\longmapsto 7x=28

\\ \sf\longmapsto x=\dfrac{28}{7}

\\ \sf\longmapsto x=4

5 0
3 years ago
Help me please! Write the measure of angles a, b, c, d, e, f, and g for the figure below.
Lina20 [59]

Answer:

a=55

b=55

c=125

d=125

e=55

f=55

g=125

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
From a pack of 9 cards numbered 1-9, three cards are drawn at random and laid on a table from left to right.
Andreas93 [3]
Answer: 1/6
Explanation: Since we need to draw three cards from a pack of 9 and the digits require an order, then our sample space becomes: 9P3.
Now, we don't care about picking an order when picking three cards to analyse, as there is only 1 way in arranging the three cards in descending order.

Thus, we get:

\frac{^{9}C_3}{^{9}P_3} = \frac{1}{6}
4 0
4 years ago
Weights of the vegetables in a field are normally distributed. From a sample Carl Cornfield determines the mean weight of a box
pantera1 [17]
To find the z-score for a weight of 196 oz., use

z=\frac{x-\mu}{\sigma}=\frac{196-180}{8}=\frac{16}{8}=2

A table for the cumulative distribution function for the normal distribution (see picture) gives the area 0.9772 BELOW the z-score z = 2.  Carl is wondering about the percentage of boxes with weights ABOVE z = 2.  The total area under the normal curve is 1, so subtract .9772 from 1.0000.

1.0000 - .9772 = 0.0228, so about 2.3% of the boxes will weigh more than 196 oz.

7 0
3 years ago
Help me I will really appreciate it
kotykmax [81]

Answer:

The answer is (1,-1)

6 0
3 years ago
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