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Leya [2.2K]
3 years ago
13

A house with an original value of increased in value to in years. What is the ratio of the increase in value to the original val

ue of the house?
Mathematics
1 answer:
Anika [276]3 years ago
6 0

Answer:

Ratio of the increase in value to the original value will be 1 : 5

Step-by-step explanation:

This question is incomplete; Here is the complete question.

A house with an original value to $150,000 increased in value to $180,000 in 5 years. what is the ratio of the increase in value to the original value of the house?

Original value of the house = $150000

Value of the house after 5 years = $180000

Appreciation in value of the house after 5 years = $180000 - $150000

= $30000

Now the ratio of the increase in value to the original value = \frac{\text{Increased value}}{\text{Original value}}

= \frac{30000}{150000}

= \frac{1}{5} or 1 : 5

Therefore, ratio of the increase in value to the original value of the house is 1 : 5

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slava [35]

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27 pages in 1 hour

Step-by-step explanation:

9*3 = 27

7 0
3 years ago
Hi quick whats 18 x 1.25 <br> step by step !!
Ivan

Answer:

22.5

Step-by-step explanation:

125

x 18

---------

1. first set up your problem

2 4

125

x 18

------

1000

2. next multiply the 8 by 5 getting 40, drop the 0 anf move the 4 to the top above 2.

3. multiply 8 by 2 getting 16, then add the 4 you have ontop of the 2 to the 16 getting 20. Drop the 0 and bring the 2 over and place it above the one.

4. multiply 8 by 1 getting 8 then add the 2 above the 1 to 8 getting 10. Then put the ten infront of the tw zeros. 1000

125

x 18

--------

1000

0

Next add a 0 as a place filler under the 0 at the end.

125

x 18

-------

1000

1250

Then multiply the 1 by 5, then 1 by 2, then finnaly 1 by 1, getting you 1250.

1000

+1250

add together

getting 2250

then move 2 decimal places over to get 22.5

3 0
3 years ago
4 digit minus 4 Digit
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Step-by-step explanation:

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3 0
3 years ago
PLEASE HELP AND SHOW WORK!!
Nastasia [14]

Answer:

Pipe 1 alone fills a tank in 10 min

Pipe 2 alone fills the tank in 20 min

If both are turned on together, how long will it take to fill the tank???

Pipe 1 fills at the RATE of 1/10th tank per min

Pipe 2 fills at the RATE of 1/20th tank per min

Pipe 1 + Pipe 2 fills at the rate of 1/10+1/20 or 3/20th tank per min

Let x= time to fill the tank

(3/20)(x)=1 Where 1 denotes a full tank (Multiply both sides by 20)

3x=20

x=6 2/3 min----------both working together

NOW YOUR PROBLEM

Let x= amount of time for smaller pipe to fill the tank

Then (x-5)=amount of time for larger pipe to fill the tank

NOW HERE'S WHERE THE RECIPROCAL COMES IN:

The smaller pipe fills the tank at the RATE of 1/x cu units per min

The larger tank fills the tank at the RATE of 1/(x-5) cu units per min

Together, they fill the tank at the rate of 1/x+(1/(x-5)) cu units per min

But now we are told that together the fill the tank in 11 1/9 minutes. so our equation to solve is:

(1/x+(1/(x-5))(11 1/9)=1 where 1 denotes a full tank. In fact, in each of the above reciprocals, the 1 denotes a full tank.

So, dividing both sides by 11 1/9, we get:

1/x+(1/(x-5)=1/(11 1/9)-------------- which is your equation

I assume that you have no problems solviing this eq.

Hope this helps----ptaylor

Step-by-step explanation:

7 0
2 years ago
I really don't understand all of this
PolarNik [594]

Answer:

Step-by-step explanation:

Distribute each one like a robot

Or factor it like a human.

5(x+2y - 3)

5 0
3 years ago
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