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4 years ago

what is the ratio of electrostatic force and the gravitational force between a proton and an electron?

Physics

2 answers:

aliina [53]4 years ago

6 0

Answer:

Fg = G M m / R^2 the gravitational force (M proton, m electron)

Fe = K e^2 / R^2 the electrical force where K = 9 *10E9 and e = charge

Fe / Fg = K e^2 / (G M m)

Fe / Fg = 9 * 10E9 * (1.6 * 10E-19)^2 / (6.67 * 10E-11 * 1.67 * 10E-27 * 9.11 * 10E-31

9 * 1.6^2 / (6.67 * 1.67 * 9.11) * 10^-29 / 10^-69

= 2.27 * 10E39 for the ratio of the two forces

Vadim26 [7]4 years ago

4 0

Answer:

Explanation:

electron attraction between electron and nucleus = centripetal force of the orbiting electron

In fact, Bohr model depicts the atom as a nucleus surrounded by electrons in circular orbit around it, similar to the planets around the Sun. The centripetal force that keeps the electrons in circular motion around the nucles is provided by the electrostatic force between the electrons and the nucleus.

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3 years ago

Define power and describe how to determine power. (4 points)

Allushta [10]

Answer: The power is a measure of the rate at which work is done (or similarly, at which energy is transferred). The standard unit of power is Watt (1W). The power is determined by the change in energy, delta E (number of joules) and delta t, which is the time taken in seconds then: P= delta E/ delta t.

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4 years ago

Write any two difference between air pump and water pump.

Alina [70]

Answer:

See the explanation below.

Explanation:

Pumping water requires equipment with closed housing, so that water is not irrigated from the pumping point.

Fans in some applications do not require closed housings, as air irritation does not create anomalies or areas of nonconformity at the air pumping point.

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3 years ago

A rock is tossed straight up from the ground with a speed of 21 m/s . When it returns, it falls into a hole 10 m deep.a.) What i

Arte-miy333 [17]

(a) 25.2 m/s

Let's take the initial vertical position of the rock as "zero" (reference height).

According to the law of conservation of energy, the speed of the rock as it reaches again the position "zero" after being thrown upwards is equal to the initial speed of the rock, 21 m/s (in fact, if there is no air resistance, no energy can be lost during the motion; and since the kinetic energy depends only on the speed of the rock:

$K=\frac{1}{2}mv^2$

and the gravitational potential energy of the rock has not changed, since the rock has returned into its initial position, it means that the speed of the rock should be the same)

This means that we can only analyze the final part of the motion, the one in which the rock falls into the 10 m hole. Since it is a free fall motion, we can find the final speed by using

$v^2 = u^2 + 2gd$