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barxatty [35]
4 years ago
7

what is the ratio of electrostatic force and the gravitational force between a proton and an electron?

Physics
2 answers:
aliina [53]4 years ago
6 0

Answer:

Fg = G M m / R^2    the gravitational force (M  proton, m electron)

Fe = K e^2 / R^2   the electrical force where K = 9 *10E9 and e = charge

Fe / Fg = K e^2 / (G M m)

Fe / Fg = 9 * 10E9 * (1.6 * 10E-19)^2 / (6.67 * 10E-11 * 1.67 * 10E-27 * 9.11 * 10E-31

9 * 1.6^2 / (6.67 * 1.67 * 9.11) * 10^-29 / 10^-69

= 2.27 * 10E39  for the ratio of the two forces

Vadim26 [7]4 years ago
4 0

Answer:

Explanation:

electron attraction between electron and nucleus = centripetal force of the orbiting electron

In fact, Bohr model depicts the atom as a nucleus surrounded by electrons in circular orbit around it, similar to the planets around the Sun. The centripetal force that keeps the electrons in circular motion around the nucles is provided by the electrostatic force between the electrons and the nucleus.

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and an ideal spring of unknown force constant. The oscillator is found to have a period of 0.157 s and a maximum speed of 2 m/s
DENIUS [597]

Answer:

k = 1073.09 N/m

A = 0.05 m

Explanation:

Given:

- Time period T = 0.147 s

- maximum speed V_max = 2 m/s

- mass of the block m = 0.67 kg

Find:

- The spring constant k

- The amplitude of the motion A.

Solution:

- A general simple harmonic motion is modeled by:

                                     x (t) = A*sin(w*t)

- The velocity of the above modeled SHM is:

                                     v = dx / dt

                                     v(t) = A*w*cos(w*t)

- Where A is the amplitude in meters, w is the angular speed rad/s and time t is in seconds.

- We can see that maximum velocity occurs when (cos(w*t)) maximizes i.e it is equal to 1 or -1. Hence,

-                                      V_max = A*w

- Where w is related to mass of the object and spring constant k as follows,

                                       w = sqrt ( k / m )

- The relationship between w angular speed and Time period T is:

                                       w = 2*pi / T

- Equating the above two equations we have,

                                        m*(2*pi / T)^2 = k

- Hence,                           k = 0.67*(2*pi / 0.157)^2

                                        k = 1073.09 N / m

- So, amplitude A is:

                                        A = V_max*sqrt ( m / k )

                                        A = 2*sqrt ( 0.67 / 1073.09 )

                                        A = 0.05 m      

6 0
4 years ago
Differentiate can you help me plzzzzzzz​
Schach [20]

Explanation:

Acceleration and the other term are the same physical phenomenon - just with opposite affects. Acceleration increases velocity, while the other term that begins with the letter "R" reduces.

***(Brainly's language filter is blocking the use of the second term in my answer.)***

Acceleration is defined as the rate of change of the velocity of an object per unit of time...

a = \frac{dv}{dt}

Acceleration would be a POSITIVE (+) quantity, while the r-word would be negative (-).

4 0
3 years ago
A particle passes through the point P=(−3,1,0)P=(−3,1,0) at time t=3t=3, moving with constant velocity v⃗ =⟨5,3,−2⟩v→=⟨5,3,−2⟩.
eimsori [14]

Answer:

The parametric equation for the position of the particle is (-18+5t,-8+3t,6-2t).

Explanation:

Given that,

The point is

P=(-3,1,0)

Time t = 3

Velocity v=(5,3,-2)

We need to calculate the parametric equation for the position of the particle

Using parametric equation for position

r(t)=r_{0}+v(t)t....(I)

at t = 3,

P=r(t)

Put the value into the formula

(-3,1,0)=r_{0}+(5,3,-2)\times3

(-3,1,0)=r_{0}+(15,9,-6)

r_{0}=(-18,-8,6)

Put the value of r₀ in equation (I)

r(t)=(-18,-8,6)+(5,3,-2)t

r(t)=(-18+5t,-8+3t,6-2t)

Hence, The parametric equation for the position of the particle is (-18+5t,-8+3t,6-2t).

3 0
3 years ago
Moving 4.0 coulombs of charge through a circuit
Galina-37 [17]
We know that V=E/Q Where V is the PD, E is the energy, and Q is the charge.

Substituting in the values gives V=48/4=12

Therefore the PD across the circuit is 12V
5 0
4 years ago
How long can a tow rope or chain be?<br> 1. 20 feet 2. 15 feet<br> 3. 5 feet<br> 4. 10 feet
Serga [27]

Answer:

"For towing, a tow chain should be of a length that keeps both vehicles within the maximum 4.5 meter distance, also  tow chains an be any length 20 foot chains are often chosen"  

Explanation:

-  https://letstowthat.com

Also Quick note the feet of tow rope or chain varies on the situation but most longest or 20 feet.  

3 0
3 years ago
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