The maximum frictional force in the knee joint of a person who supports 76. 0 kg of her mass on that knee 119.28N.
Given,
m=76kg, μ=0.16, g=9.81 m/
frictional force = mμg= 76*0.16*9.81= 119.28 N
<h3>Frictional force</h3>An opposing force to the relative motion of two bodies in contact is known as frictional force. Always acting in the opposite direction from the direction of motion, frictional force is applied to a moving body. Because it resists motion, it aids in lowering the moving object's speed. The force is one of touch. Four broad categories can be made for the force of friction depending on the sort of motion that occurs between the two objects. Static friction is the force of friction between an object and the surface it is put on.
What is the maximum frictional force in the knee joint of a person who supports 76. 0 kg of her mass on that knee?
Learn more about frictional force here:
#SPJ4
Answer:
40 cm
Explanation:
The focus of a spherical convex mirror is the point at which the rays of an object converge in the infinite, it is also the point at which an object must be placed so that its image is formed in the infinite. The distance from the focus to the origin is called the focal length and is called f. It is related to the radius of the mirror, R, according to:
rewriting for R:
.
Answer:
Q = 200800 Joules.
Explanation:
Given the following data;
Mass = 4kg
Initial temperature = 30.0°C
Final temperature = 90.0°C
Specific heat capacity of glass = 837 J/kg°C
To find the quantity of heat absorbed;
Heat capacity is given by the formula;
Where;
Q represents the heat capacity or quantity of heat.
m represents the mass of an object.
c represents the specific heat capacity of water.
dt represents the change in temperature.
dt = T2 - T1
dt = 90 - 30
dt = 60°C
Substituting the values into the equation, we have;
Q = 200800 Joules.
Therefore, the amount of heat absorbed is 200800 Joules.
Answer:
a)<em> It took 1.28 seconds to Neil Armstrong's voice to reach the Earth via radio waves. </em>
b) <em>The minimum time that will be required for a message from Mars to reach the Earth via radio waves is 192 seconds. </em>
Explanation:
The electromagnetic spectrum is the distribution of radiation due to the different frequencies at which it radiates and its different intensitie. That radiation is formed by electromagnetic waves, which are transverse waves formed by an electric field and a magnetic field perpendicular to it.
The distribution of the radiation in the electromagnetic spectrum can also be given in wavelengths, but it is more frequent to work with it at frequencies:
Any radiation that belongs to electromagnetic spectrum has a speed in vacuum of .
<em>a) Find the time it took for his voice to reach the Earth via radio waves.</em>
To know the time that took for Neil Armstrong's voice to reach the Earth via radio waves, the following equation can be used:
(1)
Where v is the speed of light, d is the distance and t is the time.
Notice that t can be isolated from equation 1.
(2)
The distance from the Earth to the Moon is , therefore.
Hence, it took 1.28 seconds to Neil Armstrong's voice to reach the Earth via radio waves.
<em>b) Determine the minimum time that will be required for a message from Mars to reach the Earth via radio waves.</em>
The distance from the Earth to the Mars at its closest approach is , therefore.
Hence, the minimum time that will be required for a message from Mars to reach the Earth via radio waves is 192 seconds.
Answer:
They both have the same angular speed.
Explanation:
The mathematical formula for angular speed is:
where is angular speed,
is a constant, and
is the period (the time it takes the marry-go-round to complete a lap).
What we can see from the formula is that, since the does not change its value, the angular speed depends only on the period T.
In this case for both the children closer to the outher edge and for the children closer to the center, the time to complete a lap is the same, because the time does not depend on where they are sitting in the marry go round. This means that the period for both is the same.
Thus, since the period for both is the same, the angular speed given by
will also be the same