Answer:
17 inches.
Step-by-step explanation:
If the area of a rectangle is the product of its length and width, then;
Area of a rectangle = Length × Width
Given that the width of the poster is greater than 10 inches and is prime, this means and W>10
Area of the rectangle = 204in²
On substituting the values in the formula;
A = LW
204 = LW
Since W is greater than 10 and is prime, it can be between the prime numbers 11, 13 and 17. Note that L must be a whole number as well for any number to be the right answer we seek.
Let's test each values of the prime width that will give a length that is a whole number.
If W = 11
204 = 11×L
L = 204/11
L = 18.54
Since the length didn't give us a whole number, this means our width is not 11.
If W = 13
204 = L × 13
L = 204/13
L = 15.69
Also, we can see that the length is not also a whole number for the value of 13 as the prime width.
If W = 17
204 = L × 17
L = 204/17
L = 12
It can be seen that the length of the rectangle gave us a whole number when we used the prime width of 17, hence the width of the poster that is greater than 10 inches and is prime that makes both length and width to be a whole number is 17 inches.
One way ti find the common denominatir is to check ti see if ine denominator is a factor to the other deniminator if it is then the deniminator can be used as the common denominator when the two deniminators are the same compare the numerators
You can start with the form
∆y(x -x1) -∆x(y -y1) = 0
Here, we have
∆y = 11-(-3) = 14
∆x = -3-1 = -4
and we can choose (x1, y1) = (1, -3). This gives
14(x -1) -(-4)(y -(-3)) = 0
14x +4y -2 = 0
All these terms have a common factor of 2 that we can remove. Adding 1 to the result puts it in standard form:
7x +2y = 1
4<p<5
(4,5)
Open circles, not shaded.
Hope this helped!
