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victus00 [196]
3 years ago
9

Marco went on a hiking trip. The first day he walked 24 kilometers. Each day since, he walked a third of what he walked the day

before.
Which expression gives the total distance Marco walked in the first n days of his trip?

URGENT!! WORTH 40 POINTS!!
Mathematics
1 answer:
lapo4ka [179]3 years ago
5 0

Answer: 24X 1-(1/3)^n

1-(1/3)

Step-by-step explanation:

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17. Simplify (3 × 22) ÷ 6 + [28 – (4)2] = ?
Effectus [21]

Answer:

31

Step-by-step explanation:

(3*22=66) / 6 + [28n - (4)2=20]

66 /6 = 11+ [20]

11+20= 31

7 0
3 years ago
The perimeter of a rectangle is 72 in. The base is 3 times the height. Find the area of the rectangle
Dovator [93]

Answer:

243 in²

Step-by-step explanation:

Step 1. Calculate the<em> base and height </em>of the rectangle

We have two conditions:

(1)   2b+ 2h = 72 in

(2)           b = 3h               Substitute in (1)

2(3h) + 2h = 72               Remove parentheses

   6h + 2h = 72               Combine like terms

           8h = 72               Divide by 6

             h = 9 in             Substitute in(2)

             b = 3 × 9

             b = 27 in

Step 2. Calculate the area of the rectangle

A = bh

A = 27 × 9

A = 243 in²

The area of the rectangle is 243 in².

7 0
3 years ago
What can the reader study to most directly determine the theme of a poem?
harina [27]
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3 years ago
Read 2 more answers
The point P(1,1/2) lies on the curve y=x/(1+x). (a) If Q is the point (x,x/(1+x)), find the slope of the secant line PQ correct
lukranit [14]

Answer:

See explanation

Step-by-step explanation:

You are given the equation of the curve

y=\dfrac{x}{1+x}

Point P\left(1,\dfrac{1}{2}\right) lies on the curve.

Point Q\left(x,\dfrac{x}{1+x}\right) is an arbitrary point on the curve.

The slope of the secant line PQ is

\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{\frac{x}{1+x}-\frac{1}{2}}{x-1}=\dfrac{\frac{2x-(1+x)}{2(x+1)}}{x-1}=\dfrac{\frac{2x-1-x}{2(x+1)}}{x-1}=\\ \\=\dfrac{\frac{x-1}{2(x+1)}}{x-1}=\dfrac{x-1}{2(x+1)}\cdot \dfrac{1}{x-1}=\dfrac{1}{2(x+1)}\ [\text{When}\ x\neq 1]

1. If x=0.5, then the slope is

\dfrac{1}{2(0.5+1)}=\dfrac{1}{3}\approx 0.3333

2. If x=0.9, then the slope is

\dfrac{1}{2(0.9+1)}=\dfrac{1}{3.8}\approx 0.2632

3. If x=0.99, then the slope is

\dfrac{1}{2(0.99+1)}=\dfrac{1}{3.98}\approx 0.2513

4. If x=0.999, then the slope is

\dfrac{1}{2(0.999+1)}=\dfrac{1}{3.998}\approx 0.2501

5. If x=1.5, then the slope is

\dfrac{1}{2(1.5+1)}=\dfrac{1}{5}\approx 0.2

6. If x=1.1, then the slope is

\dfrac{1}{2(1.1+1)}=\dfrac{1}{4.2}\approx 0.2381

7. If x=1.01, then the slope is

\dfrac{1}{2(1.01+1)}=\dfrac{1}{4.02}\approx 0.2488

8. If x=1.001, then the slope is

\dfrac{1}{2(1.001+1)}=\dfrac{1}{4.002}\approx 0.2499

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3 years ago
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nataly862011 [7]

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Step-by-step explanation:

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