What is the slope of a line that is perpendicular to the line whose equation is y = 4x + 1?
2 answers:
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Answer:
see explanation
Step-by-step explanation:
Given
4 - 5a² + 1 = 0
Use the substitution u = a², then equation is
4u² - 5u + 1 = 0
Consider the product of the coefficient of the u² term and the constant term
product = 4 × 1 = 4 and sum = - 5
The factors are - 4 and - 1
Use these factors to split the u- term
4u² - 4u - u + 1 = 0 ( factor the first/second and third/fourth terms )
4u(u - 1) - 1(u - 1) = 0 ← factor out (u - 1) from each term
(u - 1)(4u - 1) = 0
Equate each factor to zero and solve for u
u - 1 = 0 ⇒ u = 1
4u - 1 = 0 ⇒ 4u = 1 ⇒ u =
Convert u back into terms of a, that is
a² = 1 ⇒ a = ± 1
a² = ⇒ a = ±
Solutions are a = ± 1 , a = ±
Remark
You have to read this carefully to know what way to write it.
One way you could write it would be
20 * x = 18 where x is the fraction. Now all you need do is divide.
Divide both sides by 20
20/20 * x = 18/20
But you should reduce this fraction. The way to do that is to factor 18 and 20 into primes.
18: 2 * 3 * 3
20: 2 * 2 *5
Cancel out the Highest common factor or 2.
You are left with
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