Question

The nth term of a sequence is 3n^2-1

Answer 1

Answer:

see explanation

Step-by-step explanation:

To find the second and fifth terms substitute n = 2 and n = 5 into the rule, that is

(a)

$a_{2}$ = 3(2)² - 1 = (3 × 4) - 1 = 12 - 1 = 11

(b)

$a_{5}$ = 3(5)² - 1 = (3 × 25) - 1 = 75 - 1 = 74

Thus the second term is 11 and the fifth term is 74