A. The range is equal to the highest value minus the lowest value. Since the table given in part A is already in terms of range, then there is no need for a solution. The range of temperature for each month is as it is.
B. For this question, find the largest value which would represent the all-time high. That would be on February at 95°F. The lowest value would also represent the all-time low. That would be on July at 50°F.
C. The range of part B is just the difference of the all-time high and all-time low temperatures.
Range = 95°F - 50°F = 45°F
Answer:
its not working so i cant :(
Step-by-step explanation:
9514 1404 393
Answer:
7 square units
Step-by-step explanation:
There are several ways the area of triangle EBD can be found.
- find the lengths EB, BD, DE and use Heron's formula (messy due to roots of roots being involved).
- define point G at the lower left corner and subtract the areas of ∆DEG and BCD from trapezoid BCGE.
- figure the area from the coordinates of the vertices.
- use Pick's theorem and count the dots.
We choose the latter.
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Pick's theorem says the area of a polygon can be found as ...
A = i + b/2 -1
where i is the number of grid intersection points interior to the polygon, b is the number of grid points intersected by the border.
The attached figure shows the lines EB, BD, and DE intersect one point in addition to the vertices. So, b=4. A count of the red dots reveals 6 interior points (i=6). So, the area is ...
A = 6 + (4/2) -1 = 7
The area of ∆EBD is 7 square units.
Answer:
The m∠ U is 72°.
Step-by-step explanation:
Given:

To find :

Solution:
The sum of the measures of the interior angles of a polygon with 'n' sides is given as

Here we have n = 5 on substituting the values we get

Therefore,
m∠ U is 72°.