The axis of symmety is the x value of the vertex
to find the x value of the vertex of ax^2+bx+c=0
x value=-b/2a
3x^2+bx+4=0
3/2=vertex
-b/2(3)=3/2
-b/6=3/2
times 6
-b=18/2
-b=9
times -1
b=-9
Answer:
x = 10 cm, y = 5 cm gives a minimum area of 300 cm^2.
Step-by-step explanation:
V= x^2y = 500
Surface area A = x^2 + 4xy.
From the first equation y = 500/x^2
So substituting for y in the equation for the surface area:
A = x^2 + 4x * 500/x^2
A = x^2 + 2000/x
Finding the derivative:
dA/dx = 2x - 2000x^-2
dA/dx = 2x - 2000/x^2
This = 0 for a minimum/maximum value of A, so
2x - 2000/x^2 = 0
2x^3 - 2000 = 0
x^3 = 2000/ 2 = 1000
x = 10
Second derivative is 2 + 4000/x^3
when x = 10 this is positive so x = 10 gives a minimum value of A.
So y = 500/x^2
= 500/100
= 5.
Answer: y=2/3x+1
Step-by-step explanation:
y=2/3x-6
y=2/3x+b ==> Parallel to y=2/3x-6 since they both have the same slope
3=2/3 (3)+b
3=2*3/3 +b
3=6/3 +b
3=2+b
b=1
y=2/3x+1
The answer is B because the slope is always the one multiplying the x and the 1 is negative because the equation is y-y1=m(x-x1)
Example
2^3 4^2
2×2×2=6 4×4=16
All you do is multiply the number by the exponent however many times the exponents is
